COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
3rd Edition
ISBN: 9780134671123
Author: Bryant
Publisher: PEARSON
Expert Solution & Answer
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Chapter 3.6, Problem 3.31PP

Explanation of Solution

Given assembly code:

switcher:

cmpq $7, %rdi

ja .L2

jmp *.L4(,%rdi,8)

.section .rodata

.L7:

xorq $15, %rsi

movq %rsi, %rdx

.L3:

leaq 112(%rdx), %rdi

jmp .L6

.L5:

leaq (%rdx, %rsi), %rdi

salq $2, %rdi

jmp .L6

.L2:

movq %rsi, %rdi

.L6:

movq %rdi, (%rcx)

ret

Explanation:

  • The registers “%rsi”, “%rdi”, “%rdx” and “%rcx” contains values for “a”, “b”, “c” and “d” respectively.
  • The details of given assembly code is shown below:
    • The instruction “cmpq $7, %rdi” compares value of register “%rdi” with value 7.
    • The instruction “ja .L2” jumps to label “.L2” if value is above.
    • The instruction “.L4(,%rdi,8)” checks jump table and performs operation “movq %rsi, %rdi”.
    • The instruction “xorq $15, %rsi” performs “xor” operation of register “%rsi” with 15.
    • The instruction “movq %rsi, %rdx” moves value of register “%rsi” to register “%rdx”.
    • The instruction “leaq 112(%rdx), %rdi” performs operation “112 + c” and stores in “%rdi” register.
    • The instruction “salq $2, %rdi” performs shift left operation with register “%rdi”.
    • The instruction “jmp .L6” jumps to label “.L6”.
    • The instruction “movq %rsi, %rdi” moves value of register “%rsi” to register “%rdi”.
    • The instruction “movq %rdi, (%rcx)” moves value of register “%rdi” to location of register “%rcx”.

switch statement:

  • A “switch” statement provides branching capability in multiple ways based on index that is an integer.
  • It is useful in cases where large number of possible outcomes may occur.
  • The “jump table” allows efficient implementation of code...

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Chapter 3 Solutions

COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG

Ch. 3.5 - Prob. 3.11PPCh. 3.5 - Prob. 3.12PPCh. 3.6 - Prob. 3.13PPCh. 3.6 - Prob. 3.14PPCh. 3.6 - Prob. 3.15PPCh. 3.6 - Prob. 3.16PPCh. 3.6 - Practice Problem 3.17 (solution page 331) An...Ch. 3.6 - Practice Problem 3.18 (solution page 332) Starting...Ch. 3.6 - Prob. 3.19PPCh. 3.6 - Prob. 3.20PPCh. 3.6 - Prob. 3.21PPCh. 3.6 - Prob. 3.22PPCh. 3.6 - Prob. 3.23PPCh. 3.6 - Practice Problem 3.24 (solution page 335) For C...Ch. 3.6 - Prob. 3.25PPCh. 3.6 - Prob. 3.26PPCh. 3.6 - Practice Problem 3.27 (solution page 336) Write...Ch. 3.6 - Prob. 3.28PPCh. 3.6 - Prob. 3.29PPCh. 3.6 - Practice Problem 3.30 (solution page 338) In the C...Ch. 3.6 - Prob. 3.31PPCh. 3.7 - Prob. 3.32PPCh. 3.7 - Prob. 3.33PPCh. 3.7 - Prob. 3.34PPCh. 3.7 - Prob. 3.35PPCh. 3.8 - Prob. 3.36PPCh. 3.8 - Prob. 3.37PPCh. 3.8 - Prob. 3.38PPCh. 3.8 - Prob. 3.39PPCh. 3.8 - Prob. 3.40PPCh. 3.9 - Prob. 3.41PPCh. 3.9 - Prob. 3.42PPCh. 3.9 - Practice Problem 3.43 (solution page 344) Suppose...Ch. 3.9 - Prob. 3.44PPCh. 3.9 - Prob. 3.45PPCh. 3.10 - Prob. 3.46PPCh. 3.10 - Prob. 3.47PPCh. 3.10 - Prob. 3.48PPCh. 3.10 - Prob. 3.49PPCh. 3.11 - Practice Problem 3.50 (solution page 347) For the...Ch. 3.11 - Prob. 3.51PPCh. 3.11 - Prob. 3.52PPCh. 3.11 - Practice Problem 3.52 (solution page 348) For the...Ch. 3.11 - Practice Problem 3.54 (solution page 349) Function...Ch. 3.11 - Prob. 3.55PPCh. 3.11 - Prob. 3.56PPCh. 3.11 - Practice Problem 3.57 (solution page 350) Function...Ch. 3 - For a function with prototype long decoda2(long x,...Ch. 3 - The following code computes the 128-bit product of...Ch. 3 - Prob. 3.60HWCh. 3 - In Section 3.6.6, we examined the following code...Ch. 3 - The code that follows shows an example of...Ch. 3 - This problem will give you a chance to reverb...Ch. 3 - Consider the following source code, where R, S,...Ch. 3 - The following code transposes the elements of an M...Ch. 3 - Prob. 3.66HWCh. 3 - For this exercise, we will examine the code...Ch. 3 - Prob. 3.68HWCh. 3 - Prob. 3.69HWCh. 3 - Consider the following union declaration: This...Ch. 3 - Prob. 3.71HWCh. 3 - Prob. 3.72HWCh. 3 - Prob. 3.73HWCh. 3 - Prob. 3.74HWCh. 3 - Prob. 3.75HW
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