Explanation Given information: The width of the bar ( b ) is 20 mm. The depth of the bar ( a ) is 30 mm. The modulus of rigidity ( G ) is 75 GPa. The length of the bar ( L ) is 750 mm. The angle of twist ( ϕ ) is 2 ° . Calculation: Convert the unit of angle of twist from degree to radians: ϕ = ϕ deg × π 180 ° Here, ϕ deg is the angle of twist in degree. Substitute 2 ° for ϕ deg . ϕ = 2 ° × π 180 ° = 34.91 × 10 − 3 radians Find the depth to width ratio of a b . Here, a is the depth of the bar and b is the width of the bar. Substitute 30 mm for a , 20 mm for b . a b = 30 20 = 1.5 mm Refer Table 3.1, “Coefficient for rectangular bars in torsion” from the textbook. The value of coefficients c 1 is 0.231 and c 2 is 0.1958

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ISBN: 9780100257061

Author: BEER

Publisher: YUZU

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Chapter 3.10, Problem 128P

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Find the maximum shearing stress (τmax) in the bar.

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Chapter 3.10, Problem 127P

Chapter 3.10, Problem 129P

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Find the maximum shearing stress ( τ max ) in the bar.

Solution Summary: The author explains how to convert the unit of angle of twist from degree to radians.

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