Precalculus: Mathematics for Calculus - 6th Edition

6th Edition

ISBN: 9780840068071

Author: Stewart, James, Redlin, Lothar, Watson, Saleem

Publisher: Cengage Learning

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Question

Chapter 3.1, Problem 52E

To determine

To find: The local maximum and minimum values of the function whose graph is given.

Expert Solution & Answer

Answer to Problem 52E

The local maximum value of the function is equal to 2 and 1 and the value of local minimum of the function is −1 .

Explanation of Solution

Given information:

The graph of the function is:

Precalculus: Mathematics for Calculus - 6th Edition, Chapter 3.1, Problem 52E

Calculation:

As shown in the graph of the function, the point of local maxima of the function are x=−2 and x=2 and the points of local minima of the function is x=0 .

As shown in the graph, the value of the function at x=0 is equal to −1 .

So, the value of local minima of the function is equal to −1 .

As shown in the graph, the value of the function at x=−2 is equal to 2 and the value of the function at x=2 is equal to 1 .

So, the value of local maxima of the function are 2 and 1 .

Therefore, the local maximum value of the function is equal to 2 and 1 and the value of local minimum of the function is −1 .

Chapter 3.1, Problem 51E

Chapter 3.1, Problem 53E

Chapter 3 Solutions

Precalculus: Mathematics for Calculus - 6th Edition

Ch. 3.1 - To put the quadratic function f(x)=ax2+bx+c in...Ch. 3.1 - The quadratic function f(x) = a(x - h)2 + k is in...Ch. 3.1 - The graph of f(x) = 3(x - 2)2 - 6 is a parabola...Ch. 3.1 - The graph of f(x) = -3(x - 2)2 - 6 is a parabola...Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E

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