
a.
To Express: The quadratic function in standard form.
a.

Answer to Problem 31E
the quadratic function is expressed in standard form as
Explanation of Solution
Given: The function is
Calculation:
The quadratic function
The parabola opens downwards if
Solve the function:
On comparing the above equation with standard form
Therefore, the quadratic function is expressed in standard form as
b.
To Sketch: The graph of the quadratic function.
b.

Explanation of Solution
Given: The function is
Graph:
The standard form of the function is:
From the standard form it is observed that the graph is a parabola that opens upward and has vertex
The
Use graphing calculator to graph the function:
c.
To Find: The maximum or minimum value of the function.
c.

Answer to Problem 31E
The value of
Explanation of Solution
Given: The function is
Calculation:
From the above graph it is seen that the parabola opens downward, since the coefficient of
Chapter 3 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- A 20 foot ladder rests on level ground; its head (top) is against a vertical wall. The bottom of the ladder begins by being 12 feet from the wall but begins moving away at the rate of 0.1 feet per second. At what rate is the top of the ladder slipping down the wall? You may use a calculator.arrow_forwardExplain the focus and reasons for establishment of 12.4.1(root test) and 12.4.2(ratio test)arrow_forwarduse Integration by Parts to derive 12.6.1arrow_forward
- Explain the relationship between 12.3.6, (case A of 12.3.6) and 12.3.7arrow_forwardExplain the key points and reasons for the establishment of 12.3.2(integral Test)arrow_forwardUse 12.4.2 to determine whether the infinite series on the right side of equation 12.6.5, 12.6.6 and 12.6.7 converges for every real number x.arrow_forward
- use Corollary 12.6.2 and 12.6.3 to derive 12.6.4,12.6.5, 12.6.6 and 12.6.7arrow_forwardExplain the focus and reasons for establishment of 12.5.1(lim(n->infinite) and sigma of k=0 to n)arrow_forwardExplain the focus and reasons for establishment of 12.5.3 about alternating series. and explain the reason why (sigma k=1 to infinite)(-1)k+1/k = 1/1 - 1/2 + 1/3 - 1/4 + .... converges.arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





