Organic Chemistry-Package(Custom)
Organic Chemistry-Package(Custom)
4th Edition
ISBN: 9781259141089
Author: SMITH
Publisher: MCG
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Chapter 31, Problem 31.44P

Although styrene undergoes both cationic and anionic polymerization equally well, one method is often preferred with substituted styrenes. Which method is preferred with each compound? Explain.

a. Chapter 31, Problem 31.44P, 30.43 Although styrene undergoes both cationic and anionic polymerization equally well, one method , example  1 c. Chapter 31, Problem 31.44P, 30.43 Although styrene undergoes both cationic and anionic polymerization equally well, one method , example  2

b. Chapter 31, Problem 31.44P, 30.43 Although styrene undergoes both cationic and anionic polymerization equally well, one method , example  3 d. Chapter 31, Problem 31.44P, 30.43 Although styrene undergoes both cationic and anionic polymerization equally well, one method , example  4

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation: The method, anionic or cationic polymerization preferred with the given substituted styrene is to be identified, and an explanation corresponding to it is to be stated.

Concept introduction: An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

Answer to Problem 31.44P

The given substituted styrene prefers to undergo cationic polymerization, due to presence of electron releasing group on benzene ring.

Explanation of Solution

The given substituted styrene resembles to CH2=CHZ alkene, where Z=C6H4OCH3. This means benzene ring is substituted with methoxy group. The methoxy group is an electron releasing group.

An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

An electron releasing group releases electron density towards benzene ring and stabilizes carbocation formed during the cationic polymerization, whereas an electron withdrawing group withdraws electron density towards itself and stabilizes carbanion formed during the anionic polymerization.

Since the given substituted styrene involves bonding of an electron releasing group to benzene ring, it prefers to undergo cationic polymerization.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:The method, anionic or cationic polymerization preferred with the given substituted styrene is to be identified, and an explanation corresponding to it is to be stated.

Concept introduction: An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

Answer to Problem 31.44P

The given substituted styrene prefers to undergo anionic polymerization, due to presence of electron withdrawing group on benzene ring.

Explanation of Solution

The given substituted styrene resembles to CH2=CHZ alkene, where Z=C6H4OCH3. This means benzene ring is substituted with nitro group. The nitro group is an electron withdrawing group.

An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

An electron releasing group releases electron density towards benzene ring and stabilizes carbocation formed during the cationic polymerization, whereas an electron withdrawing group withdraws electron density towards itself and stabilizes carbanion formed during the anionic polymerization.

Since the given substituted styrene involves bonding of an electron withdrawing group to benzene ring, it prefers to undergo anionic polymerization.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:The method, anionic or cationic polymerization preferred with the given substituted styrene is to be identified, and an explanation corresponding to it is to be stated.

Concept introduction: An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

Answer to Problem 31.44P

The given substituted styrene prefers to undergo anionic polymerization, due to presence of electron withdrawing group on benzene ring.

Explanation of Solution

The given substituted styrene resembles to CH2=CHZ alkene, where Z=C6H4OCH3. This means benzene ring is substituted with CF3 group. The CF3 group is an electron withdrawing group.

An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

An electron releasing group releases electron density towards benzene ring and stabilizes carbocation formed during the cationic polymerization, whereas an electron withdrawing group withdraws electron density towards itself and stabilizes carbanion formed during the anionic polymerization.

Since the given substituted styrene involves bonding of an electron withdrawing group to benzene ring, it prefers to undergo anionic polymerization.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:The method, anionic or cationic polymerization preferred with the given substituted styrene is to be identified, and an explanation corresponding to it is to be stated.

Concept introduction: An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

Answer to Problem 31.44P

The given substituted styrene prefers to undergo cationic polymerization, due to presence of electron releasing group on benzene ring.

Explanation of Solution

The given substituted styrene resembles to CH2=CHZ alkene, where Z=C6H4OCH3. This means benzene ring is substituted with ethyl group. The ethyl group is an electron releasing group.

An alkene (CH2=CHZ) that contains electron withdrawing group as Z group prefers to undergo anionic polymerization to yield addition polymers. On the other hand, an alkene (CH2=CHZ) that contains electron releasing group as Z group prefers to undergo cationic polymerization to yield addition polymers.

An electron releasing group releases electron density towards benzene ring and stabilizes carbocation formed during the cationic polymerization, whereas an electron withdrawing group withdraws electron density towards itself and stabilizes carbanion formed during the anionic polymerization.

Since the given substituted styrene involves bonding of an electron releasing group to benzene ring, it prefers to undergo cationic polymerization.

Conclusion

(a) The given substituted styrene prefers to undergo cationic polymerization, due to presence of an electron releasing group on benzene ring.

(b) The given substituted styrene prefers to undergo anionic polymerization, due to presence of an electron withdrawing group on benzene ring.

(c) The given substituted styrene prefers to undergo anionic polymerization, due to presence of an electron withdrawing group on benzene ring.

(d) The given substituted styrene prefers to undergo cationic polymerization, due to presence of an electron releasing group on benzene ring.

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Chapter 31 Solutions

Organic Chemistry-Package(Custom)

Ch. 31 - Prob. 31.11PCh. 31 - Problem 30.12 What polymer is formed by anionic...Ch. 31 - Prob. 31.13PCh. 31 - Prob. 31.14PCh. 31 - Problem 30.15 What polyamide is formed from each...Ch. 31 - Prob. 31.16PCh. 31 - Prob. 31.17PCh. 31 - Prob. 31.18PCh. 31 - Prob. 31.19PCh. 31 - Prob. 31.20PCh. 31 - Prob. 31.21PCh. 31 - Prob. 31.22PCh. 31 - Prob. 31.23PCh. 31 - Prob. 31.24PCh. 31 - Prob. 31.25PCh. 31 - Prob. 31.26PCh. 31 - 30.26 Draw the structure of the polymer formed by...Ch. 31 - Prob. 31.28PCh. 31 - Prob. 31.29PCh. 31 - Prob. 31.30PCh. 31 - Prob. 31.31PCh. 31 - Prob. 31.32PCh. 31 - Prob. 31.33PCh. 31 - Prob. 31.34PCh. 31 - Prob. 31.35PCh. 31 - Prob. 31.36PCh. 31 - Prob. 31.37PCh. 31 - Prob. 31.38PCh. 31 - Prob. 31.39PCh. 31 - 30.39 Draw a stepwise mechanism for the...Ch. 31 - 30.40 Cationic polymerization of 3-phenylpropene ...Ch. 31 - Prob. 31.42PCh. 31 - Prob. 31.43PCh. 31 - 30.43 Although styrene undergoes both cationic and...Ch. 31 - 30.44 Rank the following compounds in order of...Ch. 31 - Prob. 31.46PCh. 31 - Prob. 31.47PCh. 31 - 30.47 Draw a stepwise mechanism for the following...Ch. 31 - 30.48 Draw a stepwise mechanism for the reaction...Ch. 31 - Prob. 31.50PCh. 31 - Prob. 31.51PCh. 31 - Prob. 31.52PCh. 31 - 30.52 (a) Explain why poly (vinyl alcohol) cannot...Ch. 31 - Prob. 31.54PCh. 31 - 30.53 Devise a synthesis of terephthalic acid and...Ch. 31 - Prob. 31.56PCh. 31 - Prob. 31.57PCh. 31 - 30.56 Compound A is a novel poly (ester amide)...Ch. 31 - Researchers at Rutgers University have developed...Ch. 31 - 30.58 Melmac, a thermosetting polymer formed from...Ch. 31 - 30.59 Although chain branching in radical...Ch. 31 - Prob. 31.62P
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