Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Differential Equations
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Chapter 3.1, Problem 28PPS
To determine

Graph the equation by using x and y − intercept.

Expert Solution & Answer
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Answer to Problem 28PPS

x and y intercepts are x= 1.333 and y = 8

Explanation of Solution

Given:

The equation: y=8−6x

Concept Used:

The  x -intercepts are where the graph crosses the  x -axis, and the  y -intercepts are where the graph crosses the  y -axis.

Then, algebraically,

  • an  x -intercept is a point on the graph where  y  is zero, and
  • a  y -intercept is a point on the graph where  x  is zero.

More specifically,

  • an  x -intercept is a point in the equation where the  y -value is zero, and
  • a  y -intercept is a point in the equation where the  x -value is zero.

Calculation:

The equation: y=8−6x

Find the x − intercept, plug in y = 0 in the equation.

  y=8−6x0=8−6x  [  plug  in  y  =0  ]0+6x=8−6x+6x  [ Subtract  6x  from  both  sides ] 6x=86x6  =  86x=1.333 x − Intercept: x= 1.333

Find the y − intercept, plug in x = 0 in the equation

  y=8−6xy=8−6  ·  0  [  plug  in  x  =0  ]y=8 y − Intercept: y = 8

Graph the line y=8−6x with x and y intercepts points are (1.333, 0) and (0, 8)

  Algebra 1, Chapter 3.1, Problem 28PPS

Thus, x and y intercepts are x = 1.333 and y = 8

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Chapter 3 Solutions

Algebra 1

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