Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3, Problem 9PT
To determine

Graph the equation 12x=4x+16 .

Expert Solution & Answer
Check Mark

Answer to Problem 9PT

Graph by using the x and y intercepts. They are x  = 2 and y=0

Explanation of Solution

Given:

The equation: 12x=4x+16

Concept Used:

The x -intercepts are where the graph crosses the x -axis, and the y -intercepts are where the graph crosses the y -axis.

Then, algebraically,

  • an x -intercept is a point on the graph where y is zero, and
  • a y -intercept is a point on the graph where x is zero.

More specifically,

  • an x -intercept is apoint in the equation where the y -value is zero, and
  • a y -intercept is a point in the equation where the x -value is zero.

Calculation:

The equation: 12x=4x+16

We can graph the equation by using x and y − intercept method. First we find the x and y intercept from the equation and then plot the points on the grid and join then to complete the graph.

Find the x − intercept, plug in y=0 in the equation.

  12x=4x+1612x−4x=4x+16−4x[Plug  in  y=0]8x=168x2=168x  = 2 x − Intercept: x  = 2

Find the y − intercept, plug in x  = 0 in the equation

  12x=4x+1612x−4x=4x+16−4x  [Plug  in  x=0]8⋅0=160   y − Intercept: y=0

Graph the line 12x=4x+16 with x and y intercepts points are (2,0) and (0,0)

  Algebra 1, Chapter 3, Problem 9PT

Thus, x and y intercepts are x  =2 and y=0

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Chapter 3, Problem 7STP

Chapter 3 Solutions

Algebra 1

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