The reason as to why radical polymerization of styrene forms branched chains with 4 ° carbons as in A, but none with 3 ° carbon as in B is to be stated. Concept introduction: Radical polymerization takes place via free radical intermediate. The peroxide used in this polymerization forms the free radical RO · which acts as the initiator. The process in which hydrogen atom get transferred from one radical to another which results in the formation of new bond is called disproprotionation reaction.

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Answer 1

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Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 30, Problem 30.5P

Interpretation Introduction

Interpretation: The reason as to why radical polymerization of styrene forms branched chains with 4° carbons as in A, but none with 3° carbon as in B is to be stated.

Concept introduction: Radical polymerization takes place via free radical intermediate. The peroxide used in this polymerization forms the free radical RO· which acts as the initiator.

The process in which hydrogen atom get transferred from one radical to another which results in the formation of new bond is called disproprotionation reaction.

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Answer 2

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Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 30, Problem 30.5P

Interpretation Introduction

Interpretation: The reason as to why radical polymerization of styrene forms branched chains with 4° carbons as in A, but none with 3° carbon as in B is to be stated.

Concept introduction: Radical polymerization takes place via free radical intermediate. The peroxide used in this polymerization forms the free radical RO· which acts as the initiator.

The process in which hydrogen atom get transferred from one radical to another which results in the formation of new bond is called disproprotionation reaction.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 30, Problem 30.5P

Interpretation Introduction

Interpretation: The reason as to why radical polymerization of styrene forms branched chains with 4° carbons as in A, but none with 3° carbon as in B is to be stated.

Concept introduction: Radical polymerization takes place via free radical intermediate. The peroxide used in this polymerization forms the free radical RO· which acts as the initiator.

The process in which hydrogen atom get transferred from one radical to another which results in the formation of new bond is called disproprotionation reaction.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 30, Problem 30.5P

Interpretation Introduction