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High School Math Algebra Holt Mcdougal Larson Pre-algebra: Student Edition 2012

The equation 2 n − 6 = − 8 n + 14 and check the solution.

The equation 2 n − 6 = − 8 n + 14 and check the solution.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 3, Problem 9CR

To determine

To solve:The equation 2n−6=−8n+14 and check the solution.

Expert Solution & Answer

Answer to Problem 9CR

The solution of the provided equation is n=2 .

Explanation of Solution

Given information:

The equation is 2n−6=−8n+14 .

Calculation:

The solution of the equation is:

2n−6=−8n+14 (Write original equation)2n−6+8n=−8n+14+8n (Add 8n to each side)10n−6=14 (Simplify) 10n−6+6=14+6 (Add 6 to each sides)10n=20 (Simplify)10n10=2010 (Divide both sides by 27)n=2 (Simplify)

To check substitute n=2 in left-hand-side of the equation and if left-hand-side equal right-hand-side then the solution is correct.

2n−6=−8n+14 (Write original equation)2(2)−6=−8(2)+14 (Substitute n=2 to each sides of equations)−2=−2 (Simplify)

So, both sides are equal.

Hence,

The solution of the provided equation is n=2 .

Chapter 3, Problem 8CR

Chapter 3, Problem 10CR

Chapter 3 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 3.1 - Prob. 1C Ch. 3.1 - Prob. 2C Ch. 3.1 - Prob. 3C Ch. 3.1 - Prob. 4C Ch. 3.1 - Prob. 5C Ch. 3.1 - Prob. 6C Ch. 3.1 - Prob. 7C Ch. 3.1 - Prob. 8C Ch. 3.1 - Prob. 9C Ch. 3.1 - Prob. 10C

Ch. 3.1 - Prob. 11C Ch. 3.1 - Prob. 12C Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.2 - Prob. 1C Ch. 3.2 - Prob. 2C Ch. 3.2 - Prob. 3C Ch. 3.2 - Prob. 1E Ch. 3.2 - 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Prob. 17MCQ Ch. 3 - Prob. 1CR Ch. 3 - Prob. 2CR Ch. 3 - Prob. 3CR Ch. 3 - Prob. 4CR Ch. 3 - Prob. 5CR Ch. 3 - Prob. 6CR Ch. 3 - Prob. 7CR Ch. 3 - Prob. 8CR Ch. 3 - Prob. 9CR Ch. 3 - Prob. 10CR Ch. 3 - Prob. 11CR Ch. 3 - Prob. 12CR Ch. 3 - Prob. 13CR Ch. 3 - Prob. 14CR Ch. 3 - Prob. 15CR Ch. 3 - Prob. 16CR Ch. 3 - Prob. 17CR Ch. 3 - Prob. 18CR Ch. 3 - Prob. 19CR Ch. 3 - Prob. 20CR Ch. 3 - Prob. 21CR Ch. 3 - Prob. 22CR Ch. 3 - Prob. 23CR Ch. 3 - Prob. 24CR Ch. 3 - Prob. 25CR Ch. 3 - Prob. 26CR Ch. 3 - Prob. 27CR Ch. 3 - Prob. 28CR Ch. 3 - Prob. 29CR Ch. 3 - Prob. 30CR Ch. 3 - Prob. 31CR Ch. 3 - Prob. 32CR Ch. 3 - Prob. 33CR Ch. 3 - Prob. 34CR Ch. 3 - Prob. 1CT Ch. 3 - Prob. 2CT Ch. 3 - Prob. 3CT Ch. 3 - Prob. 4CT Ch. 3 - Prob. 5CT Ch. 3 - Prob. 6CT Ch. 3 - Prob. 7CT Ch. 3 - Prob. 8CT Ch. 3 - Prob. 9CT Ch. 3 - Prob. 10CT Ch. 3 - Prob. 11CT Ch. 3 - Prob. 12CT Ch. 3 - Prob. 13CT Ch. 3 - Prob. 14CT Ch. 3 - Prob. 15CT Ch. 3 - Prob. 16CT Ch. 3 - Prob. 17CT Ch. 3 - Prob. 18CT Ch. 3 - Prob. 19CT Ch. 3 - 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