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High School Math Algebra Holt Mcdougal Larson Pre-algebra: Student Edition 2012

The equation 12 − 2 m + 5 = − 1 and check the solution.

The equation 12 − 2 m + 5 = − 1 and check the solution.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 3, Problem 5CT

To determine

To solve:The equation 12−2m+5=−1 and check the solution.

Expert Solution & Answer

Answer to Problem 5CT

The solution of the provided equation is m=9 .

Explanation of Solution

Given information:

The equation is 12−2m+5=−1 .

Calculation:

The solution of the equation is obtained as:

12−2m+5=−1 (Write original equation)17−2m=−1 (Combine like terms)17−2m−17=−1−17 (Subtract 17 from each side)−2m=−18 (Simplify)−2m−2=−18−2 (Divide each side by −2)m=9 (Simplify)

To check substitute m=9 in left-hand-side of the equation and if left-hand-side equal right-hand-side then the solution is correct.

12−2m+5 (Write Left-Hand-Side of the equation)12−2(9)+5 (Substitute m=9)−1 (Simplify)

So, both sides are equal.

Hence,

The solution of the provided equation is m=9 .

Chapter 3, Problem 4CT

Chapter 3, Problem 6CT

Chapter 3 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 3.1 - Prob. 1C Ch. 3.1 - Prob. 2C Ch. 3.1 - Prob. 3C Ch. 3.1 - Prob. 4C Ch. 3.1 - Prob. 5C Ch. 3.1 - Prob. 6C Ch. 3.1 - Prob. 7C Ch. 3.1 - Prob. 8C Ch. 3.1 - Prob. 9C Ch. 3.1 - Prob. 10C

Ch. 3.1 - Prob. 11C Ch. 3.1 - Prob. 12C Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.2 - Prob. 1C Ch. 3.2 - Prob. 2C Ch. 3.2 - Prob. 3C Ch. 3.2 - Prob. 1E Ch. 3.2 - 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