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High School Math Algebra Holt Mcdougal Larson Pre-algebra: Student Edition 2012

The equation 17 h − 47 + 6 h = 160 and check the solution.

The equation 17 h − 47 + 6 h = 160 and check the solution.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Equations and inequalities describe the relationship between two mathematical expressions.

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Question

Chapter 3, Problem 6CR

To determine

To solve:The equation 17h−47+6h=160 and check the solution.

Expert Solution & Answer

Answer to Problem 6CR

The solution of the provided equation is h=9 .

Explanation of Solution

Given information:

Consider, the expression provided in the question,

17h−47+6h=160

Calculation:

The solution of the equation is:

17h−47+6h=160 (Write original equation)17h+6h−47=160 (Group like terms)23h−47=160 (Combine like terms)23h−47+47=160+47 (Add 47 to each sides)23h=207 (Simplify)23h23=20723 (Divide both sides by 23)h=9 (Simplify)

To check substitute h=9 in left-hand-side of the equation and if left-hand-side equal right-hand-side then the solution is correct.

17h−47+6h (Write left-hand-side of the equation)17(9)−47+6(9) (Substitute h=9)160 (Simplify)

Hence,

The solution of the provided equation is h=9 .

Chapter 3, Problem 5CR

Chapter 3, Problem 7CR

Chapter 3 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 3.1 - Prob. 1C Ch. 3.1 - Prob. 2C Ch. 3.1 - Prob. 3C Ch. 3.1 - Prob. 4C Ch. 3.1 - Prob. 5C Ch. 3.1 - Prob. 6C Ch. 3.1 - Prob. 7C Ch. 3.1 - Prob. 8C Ch. 3.1 - Prob. 9C Ch. 3.1 - Prob. 10C

Ch. 3.1 - Prob. 11C Ch. 3.1 - Prob. 12C Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.2 - Prob. 1C Ch. 3.2 - Prob. 2C Ch. 3.2 - Prob. 3C Ch. 3.2 - Prob. 1E Ch. 3.2 - 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