Chapter 3.1, Problem 13E

To determine

To find:The solution of the equation and check the solution.

Answer to Problem 13E

The solution for the equation $\frac{d}{12}+25=29$ is $d=\frac{1}{3}$ .

Explanation of Solution

Given information:

Consider, the equation $\frac{d}{12}+25=29$

Calculation:

From the provided expression find the value of $d$ .

Therefore,

  $\begin{array}{l}\frac{d}{12}+25=29\\ \frac{d}{12}=29-25\\ \frac{d}{12}=4\\ d=\frac{4}{12}\\ d=\frac{1}{3}\end{array}$

The value of $d$ is $\frac{1}{3}$ .

Now, to check the solution, substitute the value of $d$ in the provided expression.

Therefore,

  $\begin{array}{l}\frac{\frac{1}{3}}{12}+25=29\\ \frac{\frac{1}{3}}{12}=29-25\\ \frac{\frac{1}{3}}{12}=4\\ \frac{1}{3}=\frac{4}{12}\\ \frac{1}{3}=\frac{1}{3}\end{array}$

As left hand side is equal to right hand side, this signifies that the solution is correct.