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High School Math Algebra Holt Mcdougal Larson Pre-algebra: Student Edition 2012

the length and width of the rectangle and write its equation for the perimeterod the rectangle in terms of w .When the length of a rectangle is 5 feet less than twice its width and the perimeter of rectangle is 38 feet.

the length and width of the rectangle and write its equation for the perimeterod the rectangle in terms of w .When the length of a rectangle is 5 feet less than twice its width and the perimeter of rectangle is 38 feet.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 3.2, Problem 56E

To determine

To calculate : the length and width of the rectangle and write its equation for the perimeterod the rectangle in terms of w .When the length of a rectangle is 5 feet less than twice its width and the perimeter of rectangle is 38 feet.

Expert Solution & Answer

Answer to Problem 56E

The value of the expression is w=8 and length=11

Explanation of Solution

Given information : Consider, the value of the expression provided in the question

width=wlength=2w−5

Formula used : Perimeter=2(length+width)

Calculation : To evaluate the expression it is needed to substitute the values in the above formula

Perimeter=2(length+width)

38=2(2w−5+w)

38=2(3w−5)

Divide both sides of the equation with 2 to isolate the variable term

382=2(3w−5)2

3w−5=19

Add 5 to both side of the equation to isolate the variable term

3w−5+5=19+5

3w=24

Divide both sides by 3

3w3=243

w=8

Then, the length of the rectangle is

length=2(8)−5=11

Chapter 3.2, Problem 55E

Chapter 3.3, Problem 1C

Chapter 3 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 3.1 - Prob. 1C Ch. 3.1 - Prob. 2C Ch. 3.1 - Prob. 3C Ch. 3.1 - Prob. 4C Ch. 3.1 - Prob. 5C Ch. 3.1 - Prob. 6C Ch. 3.1 - Prob. 7C Ch. 3.1 - Prob. 8C Ch. 3.1 - Prob. 9C Ch. 3.1 - Prob. 10C

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