(a) Interpretation: The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data. Concept introduction: As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is: P i + glucose → glucose-6-phosphate + H 2 O The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

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Answer 1

Question

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

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Answer 2

Question

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Expert Solution & Answer

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See solution

Answer 5

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Answer 6

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Answer 7

Chapter 3, Problem 5P

Interpretation Introduction

(a) Interpretation:

The concentration of both phosphate and glucose in a liver cell at 37°C is maintained at about 5mm and the equilibrium concentration of glucose-6-phoisphate to be identified with the given data.

Concept introduction:

As per the data given phosphorylation of glucose is the initial reaction in glycolysis which is:

P_i + glucose → glucose-6-phosphate + H₂O

The above process becomes thermodynamically unfavorable with ΔG°' = +13.8KJ/mol. Therefore it is observed that the phosphorylation of glucose to glucose-6-phosphate in glycolysis the standard fee energy change is +13.8Kj/mol.

Answer 8

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Answer 9

Interpretation Introduction

(b) Interpretation:

The value of ∆G°' for the coupled reaction is to be identified.

Concept introduction:

In glycolysis very low concentration of the desired product would be unfavorable and hence the reaction is coupled to ATP hydrolysis to give the following overall reaction as from the given data:

ATP + glucose → glucose-6-phosphate +ADP+H+

Answer 10

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Answer 11

Interpretation Introduction

(c) Interpretation:

When the glucose-6-phosphate is concentrated at equilibrium with pH of 7.4 and at 37°C an absurdly high value for the cell is obtained and that never happens in a reality. The explanation for such situation should be provided.

Conceptintroduction:

As per the given data:

The ATP concentration is 3mm which is 0.003 M and the ADP concentration is 1mm which is 0.001 M and the glucose concentration is 0.005 M. As already obtained from part b the value of ∆G° is -18.4 kJ/mol and as given the temperature is at 37°C.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 3 - Prob. 1P Ch. 3 - Given the following reactions and their...Ch. 3 - The decomposition of crystalline N2O5...Ch. 3 - The oxidation of glucose to CO2 and water is a...Ch. 3 - Prob. 5P Ch. 3 - In another key reaction in glycolysis,...Ch. 3 - Assume that some protein molecule, in its folded...Ch. 3 - When a hydrophobic substance like a hydrocarbon is...Ch. 3 - It is observed that as temperature is increased,...Ch. 3 - Suppose a reaction has Ho and So values...

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