(a) Interpretation: The amount of free energy change involved in transporting 10 -6 mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is 0 .1 mM and the cell is suspended in a glucose solution of 0 .01 mM . Concept introduction: The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows: ΔG = ΔG 0 + RT ln Q Here, ΔG o is standard Gibbs free energy change ΔG is Gibbs free energy change R is Universal gas constant T is temperature Q is reaction quotient For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows: ΔG = RT ln [ C ] in [ C ] out Here, [ C ] in and [ C ] out is concentration of species inside and outside the cell respectively.

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Answer 1

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

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Examine the metabolic pathway. The enzymes that catalyze each step are identified as "e" with a numeric subscript. e₁ e3 e4 A B с 1° B' 02 e5 e6 e7 E F Which enzymes catalyze irreversible reactions? ப e ez ☐ ez e4 ☐ ப es 26 5 e7 Which of the enzymes is likely to be the allosteric enzyme that controls the synthesis of G? €2 ез e4 es 26 5 e7

An allosteric enzyme that follows the concerted model has an allosteric coefficient (T/R) of 300 in the absence of substrate. Suppose that a mutation reversed the ratio. Select the effects this mutation will have on the relationship between the rate of the reaction (V) and substrate concentration, [S]. ㅁㅁㅁ The enzyme would likely follow Michaelis-Menten kinetics. The plot of V versus [S] would be sigmoidal. The enzyme would mostly be in the T form. The plot of V versus [S] would be hyperbolic. The enzyme would be more active.

Penicillin is hydrolyzed and thereby rendered inactive by penicillinase (also known as ẞ-lactamase), an enzyme present in some penicillin-resistant bacteria. The mass of this enzyme in Staphylococcus aureus is 29.6 kDa. The amount of penicillin hydrolyzed in 1 minute in a 10.0 mL. solution containing 1.00 x 10 g of purified penicillinase was measured as a function of the concentration of penicillin. Assume that the concentration of penicillin does not change appreciably during the assay. Plots of V versus [S] and 1/V versus 1/[S] for these data are shown. Vo (* 10 M minute"¹) 7.0 6.0 5.0 4.0 3.0 20 1.0 0.0 о 10 20 30 1/Vo (* 10 M1 minute) 20 103 90 BO 70 50 [S] (* 100 M) 40 50 60 y=762x+1.46 × 10" [Penicillin] (M) Amount hydrolyzed (uM) 1 0.11 3 0.25 5 0.34 10 0.45 30 0.58 50 0.61

Answer 2

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

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Answer 3

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 6

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 7

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 3 - Prob. 1P Ch. 3 - Given the following reactions and their...Ch. 3 - The decomposition of crystalline N2O5...Ch. 3 - The oxidation of glucose to CO2 and water is a...Ch. 3 - Prob. 5P Ch. 3 - In another key reaction in glycolysis,...Ch. 3 - Assume that some protein molecule, in its folded...Ch. 3 - When a hydrophobic substance like a hydrocarbon is...Ch. 3 - It is observed that as temperature is increased,...Ch. 3 - Suppose a reaction has Ho and So values...

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