(a) Interpretation: The amount of free energy change involved in transporting 10 -6 mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is 0 .1 mM and the cell is suspended in a glucose solution of 0 .01 mM . Concept introduction: The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows: ΔG = ΔG 0 + RT ln Q Here, ΔG o is standard Gibbs free energy change ΔG is Gibbs free energy change R is Universal gas constant T is temperature Q is reaction quotient For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows: ΔG = RT ln [ C ] in [ C ] out Here, [ C ] in and [ C ] out is concentration of species inside and outside the cell respectively.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Why the 2nd choice is correct?

a) What are the differences between the Direct & Indirect Immunofluorescence Assays? (0.5 mark) b) What are the advantages of the Indirect Immunofluorescence Assays? (0.5 mark) c) A Super-Resolution Imaging Technique was developed in 2018 using imidazole, a His-tag ligand conjugated with a fluorophore to report the presence of a recombinant His-tag protein target, (Sci Rep, 2018, 8:5507). How does this technique improve the image quality? (2 marks)

a) What are the differences between the Direct & Indirect Immunofluorescence Assays? b) What are the advantages of the Indirect Immunofluorescence Assays? c) A Super-Resolution Imaging Technique was developed in 2018 using imidazole, a His-tag ligand conjugated with a fluorophore to report the presence of a recombinant His-tag protein target, (Sci Rep, 2018, 8:5507). How does this technique improve the image quality?

Answer 2

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 6

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 7

Chapter 3, Problem 16P

Interpretation Introduction

(a)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cellshould be calculated if the concentration of glucose inside a cell is $0 .1 mM$ and the cell is suspended in a glucose solution of $0 .01 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The amount of free energy change involved in transporting $10^{-6}$ mole of glucose from the medium into the cell should be calculated if the intracellular and extracellular concentrations were $1 mM and 10 mM$ .

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The number moles of $ATP$ should be calculated.

Concept introduction:

The standard Gibbs free energy change is related to concentration of all the species involved in the reaction as follows:

${ΔG = ΔG}^{0} + RT ln Q$

Here, ${ΔG}^{o}$ is standard Gibbs free energy change

$ΔG$ is Gibbs free energy change

R is Universal gas constant

T is temperature

Q is reaction quotient

For movement of ions and species in and outside the cell, Gibbs free energy change can be calculated as follows:

$ΔG = RT ln \frac{{[C]}_{in}}{{[C]}_{out}}$

Here, ${[C]}_{in}$ and ${[C]}_{out}$ is concentration of species inside and outside the cell respectively.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 3 - Prob. 1P Ch. 3 - Given the following reactions and their...Ch. 3 - The decomposition of crystalline N2O5...Ch. 3 - The oxidation of glucose to CO2 and water is a...Ch. 3 - Prob. 5P Ch. 3 - In another key reaction in glycolysis,...Ch. 3 - Assume that some protein molecule, in its folded...Ch. 3 - When a hydrophobic substance like a hydrocarbon is...Ch. 3 - It is observed that as temperature is increased,...Ch. 3 - Suppose a reaction has Ho and So values...

Want to see the full answer?

Chapter 3 Solutions