Essentials of MIS (13th Edition)
13th Edition
ISBN: 9780134802756
Author: Kenneth C. Laudon, Jane Laudon
Publisher: PEARSON
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Expert Solution & Answer
Chapter 3, Problem 3IQ
Explanation of Solution
Business related Problem:
The main problem in establishing a business is satisfying the customers with their product that is manufactured.
Every customer or supplier process an action only when product is being trusted, the trust is obtained based on the reviews that is provided for the products.
Example:
Consider the case where a new product is been launched online, the customer who buys the products reviews its quality after the usage of the product. The reviews that are obtained for the product will be in two ways one is positive feedback and another is negative feedback.
Positive feedback:
The best rating was given by the customers and this will be reviewed by the company. So the product will get the good reputation, good standard of the products on the market. This will improve the business into the next level.
Negative feedback:
If the customer gives negative feedback because of bad quality, that time we must review all the negative feedbacks and make our product even-more better and improve the quality according to the customers’ requirement. Sometime our competitors also give negative feedback for our products to de-promote or reduce the image among the customers. So we must analyze this kind of problems and to resolve that.
Problem with the case:
The problem that is involved with the case will be analysis true negative feedback and fake negative feedback. The problem is laid with the negative feedback need to analysed and rectified through the use of proper analysis tool. Using the tool proper analysis is obtained and the product is rated according to it.
Analysis that is made:
The job seeker has an experience about analysing the problems...
Expert Solution & Answer
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Students have asked these similar questions
The next problem concerns the following C code:
/copy input string x to buf */
void foo (char *x) {
char buf [8];
strcpy((char *) buf, x);
}
void callfoo() {
}
foo("ZYXWVUTSRQPONMLKJIHGFEDCBA");
Here is the corresponding machine code on a Linux/x86 machine:
0000000000400530 :
400530:
48 83 ec 18
sub
$0x18,%rsp
400534:
48 89 fe
mov
%rdi, %rsi
400537:
48 89 e7
mov
%rsp,%rdi
40053a:
e8 di fe ff ff
callq
400410
40053f:
48 83 c4 18
add
$0x18,%rsp
400543:
c3
retq
400544:
0000000000400544 :
48 83 ec 08
sub
$0x8,%rsp
400548:
bf 00 06 40 00
mov
$0x400600,%edi
40054d:
e8 de ff ff ff
callq 400530
400552:
48 83 c4 08
add
$0x8,%rsp
400556:
c3
This problem tests your understanding of the program stack. Here are some notes to
help you work the problem:
⚫ strcpy(char *dst, char *src) copies the string at address src (including
the terminating '\0' character) to address dst. It does not check the size of
the destination buffer.
• You will need to know the hex values of the following characters:
1234
3. Which line prevents compiler optimization? Circle one: 1234
Suggested solution:
Store strlen(str) in a variable before the if statement.
⚫ Remove the if statement.
Replace index 0 && index < strlen(str)) {
5 }
}
=
str [index] = val;
Character Hex value | Character Hex value Character Hex value
'A'
0x41
'J'
Ox4a
'S'
0x53
'B'
0x42
'K'
0x4b
"T"
0x54
0x43
'L'
Ox4c
'U'
0x55
0x44
'M'
0x4d
'V'
0x56
0x45
'N'
Ox4e
'W'
0x57
0x46
'0'
Ox4f
'X'
0x58
0x47
'P'
0x50
'Y'
0x59
0x48
'Q'
0x51
'Z'
Ox5a
'T'
0x49
'R'
0x52
'\0'
0x00
Now consider what happens on a Linux/x86 machine when callfoo calls foo with
the input string "ZYXWVUTSRQPONMLKJIHGFEDCBA".
A. On the left draw the state of the stack just before the execution of the instruction
at address Ox40053a; make sure to show the frames for callfoo and foo and
the exact return address, in Hex at the bottom of the callfoo frame.
Then, on the right, draw the state of the stack just after the instruction got
executed; make sure to show where the string "ZYXWVUTSRQPONMLKJIHGFEDCBA"
is placed and what part, if any, of the above return address has been overwritten.
B. Immediately after the ret instruction at address 0x400543 executes, what is
the value of the program counter register %rip?…
Chapter 3 Solutions
Essentials of MIS (13th Edition)
Ch. 3.1 - Prob. 1CQ1Ch. 3.1 - Prob. 2CQ1Ch. 3.1 - Prob. 3CQ1Ch. 3.1 - Prob. 4CQ1Ch. 3.4 - Prob. 1CQ2Ch. 3.4 - Prob. 2CQ2Ch. 3.4 - Prob. 4CQ2Ch. 3.4 - Prob. 5CQ2Ch. 3 - Prob. 1IQCh. 3 - Have you ever worked with Salesforce.com? What do...
Ch. 3 - Prob. 3IQCh. 3 - Prob. 4IQCh. 3 - Prob. 1RQCh. 3 - Prob. 2RQCh. 3 - Prob. 3RQCh. 3 - Prob. 4RQCh. 3 - Prob. 5DQCh. 3 - Prob. 6DQCh. 3 - Prob. 7DQCh. 3 - Prob. 8HMPCh. 3 - Prob. 9HMPCh. 3 - Prob. 13CSQCh. 3 - Prob. 14CSQCh. 3 - Prob. 15CSQCh. 3 - Prob. 16CSQCh. 3 - Prob. 17MLMCh. 3 - Prob. 18MLM
Knowledge Booster
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