Chapter 3, Problem 3.66AP

Write the formula for the ionic compound formed from the sulfite anion (SO₃^2–) and each cation:

1. (a) K⁺;
2. (b) Ba²⁺;
3. (c) Al³⁺;
4. (d) Zn²⁺.

Interpretation Introduction

Interpretation:

The formula of the ionic compound formed when ${\text{K}}^{\text{+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ has to be given.

Answer to Problem 3.66AP

The formula of the ionic compound formed when ${\text{K}}^{\text{+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{K}}_{\text{2}}{\text{SO}}_{\text{3}}\text{.}$

Explanation of Solution

When potassium cation $\left({\text{K}}^{\text{+}}\right)$ reacts with sulfite ion $\left({\text{SO}}_{\text{3}}{}^{\text{2-}}\right)\text{,}$ the compound formed is potassium sulfite $\left({\text{K}}_{\text{2}}{\text{SO}}_{\text{3}}\right)\text{.}$

  ${\text{K}}^{\text{+}}{\text{+SO}}_{\text{3}}{}^{\text{2-}}\stackrel{}{\to }{\text{K}}_{\text{2}}{\text{SO}}_{\text{3}}$

The charges are not equal in magnitude, two potassium ions and three sulfite ions are required to balance the charge.

The formula of the ionic compound formed when ${\text{K}}^{\text{+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{K}}_{\text{2}}{\text{SO}}_{\text{3}}\text{.}$

Interpretation Introduction

Interpretation:

The formula of the ionic compound formed when ${\text{Ba}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ has to be given.

Answer to Problem 3.66AP

The formula of the ionic compound formed when ${\text{Ba}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{BaSO}}_{\text{3}}\text{.}$

Explanation of Solution

When barium cation $\left({\text{Ba}}^{\text{2+}}\right)$ reacts with sulfite ion $\left({\text{SO}}_{\text{3}}{}^{\text{2-}}\right)\text{,}$ the compound formed is barium sulfite $\left({\text{BaSO}}_{\text{3}}\right)\text{.}$

  ${\text{Ba}}^{\text{2+}}{\text{+SO}}_3{}^{\text{2-}}\stackrel{}{\to }{\text{BaSO}}_3$

The charges are equal in magnitude, and one of each ion is needed to balance the charge.

The formula of the ionic compound formed when ${\text{Ba}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{BaSO}}_{\text{3}}\text{.}$

Interpretation Introduction

Interpretation:

The formula of the ionic compound formed when ${\text{Al}}^{\text{3+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ has to be given.

Answer to Problem 3.66AP

The formula of the ionic compound formed when ${\text{Al}}^{\text{3+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{3}}\right)}_{\text{3}}\text{.}$

Explanation of Solution

When aluminum cation $\left({\text{Al}}^{\text{3+}}\right)$ reacts with sulfite ion $\left({\text{SO}}_{\text{3}}{}^{\text{2-}}\right)\text{,}$ the compound formed is aluminum sulfite $\left({\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{3}}\right)}_{\text{3}}\right)\text{.}$

  ${\text{Al}}^{\text{3+}}{\text{+SO}}_{\text{3}}{}^{\text{2-}}\stackrel{}{\to }{\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{3}}\right)}_{\text{3}}$

The charges are not equal in magnitude, two aluminum ions and three sulfite ions are required to balance the charge.

The formula of the ionic compound formed when ${\text{Al}}^{\text{3+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{3}}\right)}_{\text{3}}\text{.}$

Interpretation Introduction

Interpretation:

The formula of the ionic compound formed when ${\text{Zn}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ has to be given.

Answer to Problem 3.66AP

The formula of the ionic compound formed when ${\text{Zn}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{ZnSO}}_{\text{3}}\text{.}$

Explanation of Solution

When zinc cation $\left({\text{Zn}}^{\text{2+}}\right)$ reacts with sulfite ion $\left({\text{SO}}_{\text{3}}{}^{\text{2-}}\right)\text{,}$ the compound formed is zinc sulfite $\left({\text{ZnSO}}_{\text{3}}\right)\text{.}$

  ${\text{Zn}}^{\text{2+}}{\text{+SO}}_{\text{3}}{}^{\text{2-}}\stackrel{}{\to }{\text{ZnSO}}_{\text{3}}$

The charges are equal in magnitude, and one of each ion is needed to balance the charge.

The formula of the ionic compound formed when ${\text{Zn}}^{\text{2+}}$ reacts with ${\text{SO}}_{\text{3}}{}^{\text{2-}}$ is ${\text{ZnSO}}_{\text{3}}\text{.}$