0.99 0.96 1.00 6.5 6.0 1.99 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 2.02 2.02 2.01 3.01 1.0 0.5 -6.41 6.37 6.15 6.12 -6.11 -6.08 5.82 -5.79 -4.18C 4.163 -4.14E 1.693 1.676 -1.658 1.640 -1.622 -1.456 -1.438 1.419 1.400 -1.382 -1.364 -0.966 0.948 0.929 180 170 160 150 140 130 120 110 100 90 60 60 10 80 70 -0 50 50 40 40 166.23 30 20 20 ppm 130.27 128.62 -64.31 - 30.62 -19.10 -13.62
0.99 0.96 1.00 6.5 6.0 1.99 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 2.02 2.02 2.01 3.01 1.0 0.5 -6.41 6.37 6.15 6.12 -6.11 -6.08 5.82 -5.79 -4.18C 4.163 -4.14E 1.693 1.676 -1.658 1.640 -1.622 -1.456 -1.438 1.419 1.400 -1.382 -1.364 -0.966 0.948 0.929 180 170 160 150 140 130 120 110 100 90 60 60 10 80 70 -0 50 50 40 40 166.23 30 20 20 ppm 130.27 128.62 -64.31 - 30.62 -19.10 -13.62
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
ChapterL: Let's Review
SectionL.4: Problem Solving By Dimensional Analysis
Problem 1RC: 1. A lake has an area of 2.33 × 107 m2. What is this area in square kilometers?
23.3 km2
2.33 × 1010...
Related questions
Question
(Please be sure that 7 carbons are available in the structure )Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons.
Dept 135 shows peak to be positive at 128.62 and 13.63
Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10.

Transcribed Image Text:0.99
0.96
1.00
6.5
6.0
1.99
5.5
5.0
4.5
4.0
3.5
3.0
2.5
2.0
1.5
2.02
2.02
2.01
3.01
1.0
0.5
-6.41
6.37
6.15
6.12
-6.11
-6.08
5.82
-5.79
-4.18C
4.163
-4.14E
1.693
1.676
-1.658
1.640
-1.622
-1.456
-1.438
1.419
1.400
-1.382
-1.364
-0.966
0.948
0.929

Transcribed Image Text:180 170 160 150 140 130 120 110 100 90
60
60
10
80
70
-0
50
50
40
40
166.23
30
20
20
ppm
130.27
128.62
-64.31
- 30.62
-19.10
-13.62
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