Chapter 3, Problem 3.35UKC

Interpretation Introduction

Interpretation:

The table has to be completed by filling in the formula of the ionic compound from the cations and anions.

Explanation of Solution

The cation is $N{a}^{+}.$

Bromide $\left(B{r}^{-}\right):$  Sodium reacts with bromide (derived from bromine) to form sodium bromide.  The cation is ${\text{Na}}^{\text{+}}\text{,}$ the anion is ${\text{Br}}^{\text{-}}.$  The formula of the ionic compound formed from sodium cation and bromide is $\text{NaBr}\text{.}$

Hydroxide $\left(O{H}^{-}\right)\text{:}$  Sodium reacts with hydroxide (derived from hydrogen and oxygen) to form sodium hydroxide.  The cation is ${\text{Na}}^{\text{+}}\text{,}$ the anion is ${\text{OH}}^{\text{-}}.$  The formula of the ionic compound formed from sodium cation and hydroxide ion is $\text{NaOH}\text{.}$

Hydrogen carbonate $\left(HC{O}_3{}^{-}\right):$  Sodium reacts with hydrogen carbonate (derived from hydrogen, carbon and oxygen) to form sodium bicarbonate.  The cation is ${\text{Na}}^{\text{+}}\text{,}$ the anion is ${\text{HCO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from sodium cation and hydrogen carbonate ion is ${\text{NaHCO}}_{\text{3}}\text{.}$

Sulfite $\left(S{O}_3{}^{2-}\right)\text{:}$  Sodium reacts with sulfite (derived from sulfur and oxygen) to form sodium sulfite.  The cation is ${\text{Na}}^{\text{+}}\text{,}$ the anion is ${\text{SO}}_{\text{3}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from sodium cation and sulfite ion is ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{3}}\text{.}$

Phosphate $\left(P{O}_4{}^{3-}\right)\text{:}$  Sodium reacts with phosphate (derived from phosphorus and oxygen) to form sodium phosphate.  The cation is ${\text{Na}}^{\text{+}}\text{,}$ the anion is ${\text{PO}}_4{}^{\text{3-}}\text{.}$  The formula of the ionic compound formed from sodium cation and phosphate ion is ${\text{Na}}_{\text{3}}{\text{PO}}_{\text{4}}\text{.}$

The cation is $C{o}^{2+}.$

Bromide $\left(B{r}^{-}\right):$  Cobalt reacts with bromide (derived from bromine) to form cobalt (II) bromide.  The cation is ${\text{Co}}^{\text{2+}}\text{,}$ the anion is ${\text{Br}}^{\text{-}}.$  The formula of the ionic compound formed from cobalt cation and bromide is ${\text{CoBr}}_2\text{.}$

Hydroxide $\left(O{H}^{-}\right)\text{:}$  Cobalt reacts with hydroxide (derived from hydrogen and oxygen) to form cobalt (II) hydroxide.  The cation is ${\text{Co}}^{\text{2+}}\text{,}$ the anion is ${\text{OH}}^{\text{-}}.$  The formula of the ionic compound formed from cobalt cation and hydroxide ion is $\text{Co}{\left(\text{OH}\right)}_{\text{2}}\text{.}$

Hydrogen carbonate $\left(HC{O}_3{}^{-}\right):$  Cobalt reacts with hydrogen carbonate (derived from hydrogen, carbon and oxygen) to form cobalt (II) bicarbonate.  The cation is ${\text{Co}}^{\text{2+}}\text{,}$ the anion is ${\text{HCO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from cobalt cation and hydrogen carbonate ion is $\text{Co}{\left({\text{HCO}}_{\text{3}}\right)}_{\text{2}}\text{.}$

Sulfite $\left(S{O}_3{}^{2-}\right)\text{:}$  Cobalt reacts with sulfite (derived from sulfur and oxygen) to form cobalt (II) sulfite.  The cation is ${\text{Co}}^{\text{2+}}\text{,}$ the anion is ${\text{SO}}_{\text{3}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from cobalt cation and sulfite ion is ${\text{CoSO}}_{\text{3}}\text{.}$

Phosphate $\left(P{O}_4{}^{3-}\right)\text{:}$  Cobalt reacts with phosphate (derived from phosphorus and oxygen) to form cobalt (II) phosphate.  The cation is ${\text{Co}}^{\text{2+}}\text{,}$ the anion is ${\text{PO}}_4{}^{\text{3-}}\text{.}$  The formula of the ionic compound formed from cobalt cation and phosphate ion is ${\text{Co}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\text{.}$

The cation is $A{l}^{3+}.$

Bromide $\left(B{r}^{-}\right):$  Aluminum reacts with bromide (derived from bromine) to form aluminum bromide.  The cation is ${\text{Al}}^{\text{3+}}\text{,}$ the anion is ${\text{Br}}^{\text{-}}.$  The formula of the ionic compound formed from aluminum cation and bromide is ${\text{AlBr}}_{\text{3}}\text{.}$

Hydroxide $\left(O{H}^{-}\right)\text{:}$  Aluminum reacts with hydroxide (derived from hydrogen and oxygen) to form aluminum hydroxide.  The cation is ${\text{Al}}^{\text{3+}}\text{,}$ the anion is ${\text{OH}}^{\text{-}}.$  The formula of the ionic compound formed from aluminum cation and hydroxide ion is $\text{Al}{\left(\text{OH}\right)}_{\text{3}}\text{.}$

Hydrogen carbonate $\left(HC{O}_3{}^{-}\right)\text{:}$  Aluminum reacts with hydrogen carbonate (derived from hydrogen, carbon and oxygen) to form aluminum bicarbonate.  The cation is ${\text{Al}}^{\text{3+}}\text{,}$ the anion is ${\text{HCO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from aluminum cation and hydrogen carbonate ion is $\text{Al}{\left({\text{HCO}}_{\text{3}}\right)}_{\text{3}}\text{.}$

Sulfite $\left(S{O}_3{}^{2-}\right)\text{:}$  Aluminum reacts with sulfite (derived from sulfur and oxygen) to form aluminum sulfite.  The cation is ${\text{Al}}^{\text{3+}}\text{,}$ the anion is ${\text{SO}}_{\text{3}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from aluminum cation and sulfite ion is ${\text{Al}}_{\text{2}}{\left({\text{SO}}_{\text{3}}\right)}_{\text{3}}\text{.}$

Phosphate $\left(P{O}_4{}^{3-}\right)\text{:}$  Aluminum reacts with phosphate (derived from phosphorus and oxygen) to form aluminum phosphate.  The cation is ${\text{Al}}^{\text{3+}}\text{,}$ the anion is ${\text{PO}}_4{}^{\text{3-}}\text{.}$  The formula of the ionic compound formed from aluminum cation and phosphate ion is ${\text{AlPO}}_{\text{4}}\text{.}$

The figure below shows the complete table by filling in the formula of the ionic compound from the cations and anions is,

Figure 1