Chapter 3, Problem 3.36UKC

Interpretation Introduction

Interpretation:

The table has to be completed by filling in the formula of the ionic compound from the cations and anions.

Explanation of Solution

The cation is $K^{+}.$

Iodide $\left(I^{-}\right):$  Potassium reacts with iodide (derived from iodine) to form potassium iodide.  The cation is ${\text{K}}^{\text{+}}\text{,}$ the anion is ${\text{I}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from potassium cation and iodide is $\text{KI}\text{.}$

Cyanide $\left(C{N}^{-}\right)\text{:}$  Potassium reacts with cyanide (derived from carbon and nitrogen) to form potassium cyanide.  The cation is ${\text{K}}^{\text{+}}\text{,}$ the anion is ${\text{CN}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from potassium cation and cyanide ion is $\text{KCN}\text{.}$

Nitrate $\left(N{O}_3{}^{-}\right)\text{:}$  Potassium reacts with nitrate (derived from nitrogen and oxygen) to form potassium nitrate.  The cation is ${\text{K}}^{\text{+}}\text{,}$ the anion is ${\text{NO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from potassium cation and nitrate ion is ${\text{KNO}}_{\text{3}}\text{.}$

Sulfate $\left(S{O}_4{}^{2-}\right)\text{:}$  Potassium reacts with sulfate (derived from sulfur and oxygen) to form potassium sulfate.  The cation is ${\text{K}}^{\text{+}}\text{,}$ the anion is ${\text{SO}}_{\text{4}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from potassium cation and sulfate ion is ${\text{K}}_{\text{2}}{\text{SO}}_4\text{.}$

Hydrogen Phosphate $\left(HP{O}_4{}^{2-}\right)\text{:}$  Potassium reacts with hydrogen phosphate (derived from hydrogen, phosphorus and oxygen) to form potassium hydrogen phosphate.  The cation is ${\text{K}}^{\text{+}}\text{,}$ the anion is ${\text{HPO}}_4{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from potassium cation and hydrogen phosphate ion is ${\text{KHPO}}_{\text{4}}\text{.}$

The cation is $M{g}^{2+}.$

Iodide $\left(I^{-}\right):$  Magnesium reacts with iodide (derived from iodine) to form magnesium iodide.  The cation is ${\text{Mg}}^{\text{2+}}\text{,}$ the anion is ${\text{I}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from magnesium cation and iodide is ${\text{MgI}}_{\text{2}}\text{.}$

Cyanide $\left(C{N}^{-}\right)\text{:}$  Magnesium reacts with cyanide (derived from carbon and nitrogen) to form magnesium cyanide.  The cation is ${\text{Mg}}^{\text{2+}}\text{,}$ the anion is ${\text{CN}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from magnesium cation and cyanide ion is $\text{Mg}{\left(\text{CN}\right)}_{\text{2}}\text{.}$

Nitrate $\left(N{O}_3{}^{-}\right)\text{:}$  Magnesium reacts with nitrate (derived from nitrogen and oxygen) to form magnesium nitrate.  The cation is ${\text{Mg}}^{\text{2+}}\text{,}$ the anion is ${\text{NO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from magnesium cation and nitrate ion is $\text{Mg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\text{.}$

Sulfate $\left(S{O}_4{}^{2-}\right)\text{:}$  Magnesium reacts with sulfate (derived from sulfur and oxygen) to form magnesium sulfate.  The cation is ${\text{Mg}}^{\text{2+}}\text{,}$ the anion is ${\text{SO}}_{\text{4}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from magnesium cation and sulfate ion is ${\text{MgSO}}_{\text{4}}\text{.}$

Hydrogen Phosphate $\left(HP{O}_4{}^{2-}\right)\text{:}$  Magnesium reacts with hydrogen phosphate (derived from hydrogen, phosphorus and oxygen) to form magnesium hydrogen phosphate.  The cation is ${\text{Mg}}^{\text{2+}}\text{,}$ the anion is ${\text{HPO}}_4{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from magnesium cation and hydrogen phosphate ion is ${\text{MgHPO}}_{\text{4}}\text{.}$

The cation is $C{r}^{3+}.$

Iodide $\left(I^{-}\right):$  Chromium reacts with iodide (derived from iodine) to form chromium iodide.  The cation is ${\text{Cr}}^{\text{3+}}\text{,}$ the anion is ${\text{I}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from chromium cation and iodide is ${\text{CrI}}_3\text{.}$

Cyanide $\left(C{N}^{-}\right)\text{:}$  Chromium reacts with cyanide (derived from carbon and nitrogen) to form chromium (III) cyanide.  The cation is ${\text{Cr}}^{\text{3+}}\text{,}$ the anion is ${\text{CN}}^{\text{-}}\text{.}$  The formula of the ionic compound formed from chromium cation and cyanide ion is $\text{Cr}{\left(\text{CN}\right)}_{\text{3}}\text{.}$

Nitrate $\left(N{O}_3{}^{-}\right)\text{:}$  Chromium reacts with nitrate (derived from nitrogen and oxygen) to form chromium (III) nitrate.  The cation is ${\text{Cr}}^{\text{3+}}\text{,}$ the anion is ${\text{NO}}_{\text{3}}{}^{\text{-}}\text{.}$  The formula of the ionic compound formed from chromium cation and nitrate ion is $\text{Cr}{\left({\text{NO}}_{\text{3}}\right)}_3\text{.}$

Sulfate $\left(S{O}_4{}^{2-}\right)\text{:}$  Chromium reacts with sulfate (derived from sulfur and oxygen) to form chromium (III) sulfate.  The cation is ${\text{Cr}}^{\text{3+}}\text{,}$ the anion is ${\text{SO}}_{\text{4}}{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from chromium cation and sulfate ion is ${\text{Cr}}_2{\left({\text{SO}}_4\right)}_3\text{.}$

Hydrogen Phosphate $\left(HP{O}_4{}^{2-}\right)\text{:}$  Chromium reacts with hydrogen phosphate (derived from hydrogen, phosphorus and oxygen) to form chromium (III) hydrogen phosphate.  The cation is ${\text{Cr}}^{\text{3+}}\text{,}$ the anion is ${\text{HPO}}_4{}^{\text{2-}}\text{.}$  The formula of the ionic compound formed from chromium cation and hydrogen phosphate ion is ${\text{Cr}}_{\text{2}}{\left({\text{HPO}}_{\text{4}}\right)}_{\text{3}}\text{.}$

The figure below shows the complete table by filling in the formula of the ionic compound from the cations and anions is,

Figure 1