To calculate % frequency of female population with X-linked Red and Green colorblindness from the provided information Introduction: Color blindness is in reality a color vision deficiency of distinguishing the color difference. An red-green color blind individual has trouble differentiating in shades of red, yellow, and green colors. It is an X-linked recessive disorder; the trait is passed from a mother to a son. A gene on the X chromosome governs the color vision with two alleles- (X N - normal, X n - red-green color blindness). Females are generally heterozygous (X N X n ) for the trait while most often males are affected (X n Y) with it. Females are only affected when both the parents pass on the mutated allele (X n X n ).

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 35P

Summary Introduction

To analyze:

To calculate % frequency of female population with X-linked Red and Green colorblindness from the provided information

Introduction:

Color blindness is in reality a color vision deficiency of distinguishing the color difference. An red-green color blind individual has trouble differentiating in shades of red, yellow, and green colors.

It is an X-linked recessive disorder; the trait is passed from a mother to a son. A gene on the X chromosome governs the color vision with two alleles- (X^N- normal, Xⁿ- red-green color blindness). Females are generally heterozygous (X^N Xⁿ) for the trait while most often males are affected (XⁿY) with it. Females are only affected when both the parents pass on the mutated allele (Xⁿ Xⁿ).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

One particularly useful feature of the Hardy-Weinberg equation is that it allows us to estimate the frequency of heterozygotes for recessive genetic diseases, assuming that Hardy-Weinberg equilibrium exists. As an example, let’s consider cystic fibrosis, which is a human genetic disease involving a gene that encodes a chloride transporter. Persons with this disorder have an irregularity in salt and water balance. One of the symptoms is thick mucus in the lungs that can contribute to repeated lung infections. In populations of Northern European descent, the frequency of affected individuals is approximately 1 in 2500. Because this is a recessive disorder, affected individuals are homozygotes. Assuming that the population is in Hardy-Weinberg equilibrium, what is the frequency of individuals who are heterozygous carriers?

You discover a new X-linked mutation for antenna shape in Drosophila (fruit flies) which produces long antennae. You call this new allele long (XL2), and discover it is incompletely dominant with the short antennae allele (XL1), so the heterozygotes (XL1XL2) have antennae that are intermediate in length (and XL2 homozygote females have long antennae). Males only have either long or short antennae. You cross a female with long antennae with a male with short antennae. What proportion of their male offspring do you expect to have short antennae? Group of answer choices 0.75 0.50 0 1.00 0.25

Huntington's disease is a very rare, debilitating disease that affects approximately 1 in 10,000 people. The disease is caused by a particular type of genetic mutation (large number of CAG repeats) in a gene called huntingtin (HTT). Designate the disease-causing allele HTTP and the non-disease- causing allele HTTN. We know that individuals with genotype HTTN will not develop Huntington's Disease, but people with either HTTD/HTTP or HTTN/HTTD will develop the disease. Which allele is dominant--HTTN or HTTP? Explain your reasoning thoroughly, using the correct definition of dominance.