An important piece of landing equipment must be thrown to a ship, which is moving at 45.0 cm/s. before the ship can dock. This equipment is thrown at 15.0 m/s at 60.0° above the horizontal from the top of a tower at the edge of the water. 8.75 m above the ship’s deck ( Fig. P3.52 ). For this equipment to land at the front of the ship, at what distance D from the dock should the ship be when the equipment is thrown? Ignore air resistance. Figure P3.52
An important piece of landing equipment must be thrown to a ship, which is moving at 45.0 cm/s. before the ship can dock. This equipment is thrown at 15.0 m/s at 60.0° above the horizontal from the top of a tower at the edge of the water. 8.75 m above the ship’s deck ( Fig. P3.52 ). For this equipment to land at the front of the ship, at what distance D from the dock should the ship be when the equipment is thrown? Ignore air resistance. Figure P3.52
An important piece of landing equipment must be thrown to a ship, which is moving at 45.0 cm/s. before the ship can dock. This equipment is thrown at 15.0 m/s at 60.0° above the horizontal from the top of a tower at the edge of the water. 8.75 m above the ship’s deck (Fig. P3.52). For this equipment to land at the front of the ship, at what distance D from the dock should the ship be when the equipment is thrown? Ignore air resistance.
You hit a golf ball from the (level) ground, with an initial speed and an initial angle. Ignore air resistance. (This is very unrealistic.)
The initial speed is v0 = 23.7 m/s, and the angle the ball is hit at is θ = 46o. Calculate vx0, the initial horizontal component of velocity (in m/s).
What equations describe the trajectory of the golf ball?
A playground is on the flat roof of a city school, 6.00 m abovethe street below (Fig. P3.19). The vertical wall of the buildingis h = 7.00 m high, to form a 1-m-high railing around the playground.A ball has fallen to the street below, and a passerbyreturns it by launching it at an angle of θ = 53.0° above thehorizontal at a point d = 24.0 m from the base of the buildingwall. The ball takes 2.20 s to reach a point vertically abovethe wall. (a) Find the speed at which the ball was launched.(b) Find the vertical distance by which the ball clears the wall.(c) Find the horizontal distance from the wall to the point onthe roof where the ball lands.
Trachecktory. Two cannonballs, aptly named a and B, were launched on level ground. a
was launched with a velocity of 18.0 [m/s] at 36° with respect to the ground while B was
launched with a velocity of 17.6 [m/s] at 48° with respect to the ground. What can you say
about a and B's range and time of flight?
O a and B have the same range; a has a larger time of flight.
O a and B have the same range; B has a larger time of flight.
O a and B do not have the same range; B has a larger time of flight.
O a and B do not have the same range; a has a larger time of flight.
Chapter 3 Solutions
University Physics with Modern Physics, Volume 2 (Chs. 21-37); Mastering Physics with Pearson eText -- ValuePack Access Card (14th Edition)
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