Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Question
Chapter 3, Problem 3.32PFS
To determine
The LRFD design strength and the ASD allowable strength of the given section,
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The welded girder shown in the accompanying illustration has an external shear VD = 300 k and VL = 350 kat a particular section. Determine the fillet weld size required to fasten the plates to the web if the SMAW process is used. E70. Use LRFD and ASD.
A WT6x15 shape made from A36 steel will be welded along its flanges to a gusset plate.
Determine the LRFD available strength, φRn, for gross tension yield of the WT shape.
Determine the required weld length, l, on each side of the WT in order to exceed the LRFD available strength for gross tension yield of the WT shape. Assume a weld size of w=5/16 inch and E70XX electrodes.
Based on the weld length, compute the available LRFD strength, φRn, for tensile rupture of the WT shape.
Chapter 3 Solutions
Structural Steel Design (6th Edition)
Ch. 3 - Prob. 3.1PFSCh. 3 - Prob. 3.2PFSCh. 3 - Prob. 3.3PFSCh. 3 - Prob. 3.4PFSCh. 3 - Prob. 3.5PFSCh. 3 - Prob. 3.6PFSCh. 3 - Prob. 3.7PFSCh. 3 - Prob. 3.8PFSCh. 3 - Prob. 3.9PFSCh. 3 - Prob. 3.10PFS
Ch. 3 - Prob. 3.11PFSCh. 3 - Prob. 3.12PFSCh. 3 - Prob. 3.13PFSCh. 3 - Prob. 3.14PFSCh. 3 - Prob. 3.15PFSCh. 3 - Prob. 3.16PFSCh. 3 - Prob. 3.17PFSCh. 3 - Prob. 3.18PFSCh. 3 - Prob. 3.19PFSCh. 3 - Prob. 3.20PFSCh. 3 - Prob. 3.21PFSCh. 3 - Prob. 3.22PFSCh. 3 - Prob. 3.23PFSCh. 3 - Prob. 3.24PFSCh. 3 - Prob. 3.25PFSCh. 3 - Prob. 3.26PFSCh. 3 - Prob. 3.27PFSCh. 3 - Prob. 3.28PFSCh. 3 - Prob. 3.29PFSCh. 3 - Prob. 3.30PFSCh. 3 - Prob. 3.31PFSCh. 3 - Prob. 3.32PFSCh. 3 - Prob. 3.33PFSCh. 3 - Prob. 3.34PFSCh. 3 - Determine the LRFD design strength and the ASD...Ch. 3 - Prob. 3.36PFSCh. 3 - Prob. 3.37PFS
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- Asap plsarrow_forwardDetermine the LRFD design strength and the ASD allowable strength. Neglect block shear. A36 steel and 7/8-in Ø bolts N VA N SZ 2-MC 12 x 40 00 K All 2 in 2 in 3-in 3/in 2/inarrow_forward9) what is the weld capacity of the shear connection in kips? (2 decimal places) A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksiarrow_forward
- Problem # 6.0 For the tension member shown, compute the tensile design strength. Weld -6" PL 4X6 A36 steelarrow_forward6) Calculate the shear lag reduction factor, u, for the spliced W-shape tension member shown. Hint: you can treat the wide flange section like two WT6x25s. | W12x50 H THE 3" 3" Typical Splice Plate TH HHHH -Splice Plate W12x50arrow_forwardProblem 3. An un-equal leg angle L8x4x2 made of ASTM A242 steel (Fy = 50 ksi, Fu = 70 ksi) is used as a tension member and connected to a gusset plate as shown in Figure 2 (a to d). ASABINCAT SALLALALALALALALALAL w₁ Weld * Gusset Rate 3 (c) Longitudinal and transverse welds O 18x4x2 Gusset Plate Steel Type: A242 18x4x2 bolts: 3/4 dia. Steel Type: A242 T (d) Bolted connection (d) Calculate factored fracture strength of the tension member in Figure 2(c). (e) Calculate factored fracture strength of the tension member in Figure 2(d). (f) What is the maximum permissible length for this tension member?arrow_forward
- For the tension member shown, compute the following. a) The tensile design strength. b) The allowable tensile strength. PL x8 A36 steel -12" -Weld FIGURE P3.3-2 |arrow_forwardAssume that the gusset plate and welds are satisfied. A gap allowance of 1/16 inch is to be considered to fit the gusset plate in the HSS. The steel used in the tension member is ASTM A500 Grade C HSS 6 x 0.5 with a length of 30 feet. a.) Find the shear lag factor b.) Find the Effective net area (Ae) c.) Solve for the tensile strenngth 16-inch-long fillet weld HSS 6 x 0.5 1/2 in. thick gusset plate 17 inch longarrow_forwardA tie member of a roof truss consists of 21SA 100 x 75 x 8 mm. The angles are connected by fillet weld as shown in figure on either side of a 10 mm gusset plate and the member is subjected to a factored pull of 450 kN. Take size of weld as 6 mm and connections are made in workshop. [Use Fe410 grade of steel] 75 m L. C. = 31mm 16A (100 x 75 x 8) mm Choose the nearest correct statements: L1 = 390.5 mm L1 = 195.25 mm Correct Option L2 = 87.75 mm Correct Option L2 = 175.5 mmarrow_forward
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