Determine the LRFD design strength and the ASD allowable strength of the sections given, including block shear.
3-35. A
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- 3. Segui Text Problem 3.5-1 (Modified) Compute the nominal block shear strength of the tension member shown in Figure P3.5-1. ASTM A572 Grade 50 steel is used. The bolts are 1" inch 3.5-1 in diameter. L4 X 4 X 1/2" 2'4" -- 1½2" 3" 1/2" FIGURE P3.5-1arrow_forward3.5-1 Block Shear The tension member is a PL × 5% of A242 steel. It is connected to a 3/8-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in Figure P3.5-1. Determine the nominal block shear strength of the tension member. 11/2" 2½" 11/2" 11/2" 3" 3" 11/2" FIGURE P3.5-1arrow_forwardA992 steel is used for the tension member shown. The bolts are ¾ inch in diameter. The connection is to a ⅜ inch thick gusset plate. A. Determine the nominal strength based on the gross area. B. Determine the nominal strength based on the effective net area.arrow_forward
- 3.5-1 Block Shear The tension member is a PL38 x 5¹2 of A242 steel. It is connected to a 38-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in Figure P3.5-1. Determine the nominal block shear strength of the tension member. 1½" 2½" 1/2" 01 02 1½" 3" FIGURE P3.5-1 3" 1½" 115 3.5-1 the shear areas are Agv = (3/8) (7.5) 2-5.625 in.² and, since there are 2.5 hole diameters in each line of bolts, Av = (3/8)[7.5-2.5(3/4+1/8)]2= 3.984 in.² The tension area is Am = (3/8) [2.5-17/8)] = 0.6094 in.² Fy= 50 ksi, F, = 70 ksi R₁ = 0.6F₂Anv + Ubs FuAnt = 0.6(70) (3.984) + 1.0(70) (0.6094) = 210 kips Check upper limit: 0.6F Agv + Ubs FuAnt = 0.6(50) (5.625) + 1.0(70) (0.6094) = 211 kips > 210 kipsarrow_forwardDetermine the LRFD design strength and the ASD allowable strength of sections given. Neglect block shear.arrow_forwardThe built-up girder below is comprised of four A572 Grade 50 plates welded together. Compute the section modulus (S), plastic modulus (Z₁), and shape factor (Z₁/S). Using Table B41.b of the Specification, determine whether the flanges and web are compact, noncompact, or slender. -PL 1" x 40" 10" CLEAR SPACING PL 1.5" x 20" TYParrow_forward
- Determine the controlling (lowest) net area of the member. X = 2.69 Y = (6-2.69)/2 Z=0.7 Y" -X Y" 5 @ 1/2" OD O a Do -OHD -(5)-z" bolts -L6 X 4 X 7/16arrow_forwardDetermine the LRFD design strength and the ASD allowable strength . Neglect block shear. A36 steel and 7/8-in Ø boltsarrow_forwardI have worked this problem but I am not getting the same answer as the one provided please help me understand it and step by step work it out pleasearrow_forward
- PLATE NO 3 Method of Sections Chapter 5 Problem 5-2 Page 76 Using the method of sections, determine the kind and amount of stress in the following members of the truss shown in figure P5-2 (page 76). U:U2 UıL2 LIL2 U2U3 U2L3 L2L3 1000lb 1000lb U3 1000lb 1000lb 1000lb U2 U4 500lb Ui 500lb h=20ft Us Lo L1 L2 L3 L4 Ls RAV 6 panels at 10' = 60 ft RBvarrow_forwardUSE NATIONAL STRUCTURAL CODE OF THE PHILIPPINES 2015arrow_forwardPL 5/8 x 12 3/4-in-diameter boltsarrow_forward
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning