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Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Question
Chapter 3, Problem 3.22PFS
To determine
The effective net area of the given section using the U value.
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Students have asked these similar questions
A) The 3/4 in x 15 in plate has 4 rows (or horizontal lines) of bolts. Each row has 3 bolts.
The bolt diameter is 7/8 in. Determine the gross area (Ag) and the net area (An)
3/4
15
O
O
O
O
O
O
Q
O
O
3"
3
27
3
784
Bolts
Pet
*
Determine the Net Area for the following Plate Section consider all possible Cases. The Plate thickness is 1-in. and the bolts' diameter is 7/8-in.
s = 6.0 "
g = 2.0 "
Problem 1
Given the double splice connection shown made up of 6mm x 150mm steel plates with double row of 19mm diameter
bolts.
O = 552.93 MPa , t= 207MPA and op =
552.93 MPa
a. Compute the tensile force of the steel plates
ANS
b. Compute the number of 19mm diameter bolts from shear
ANS
c. Compute the number of 19mm diameter bolts from bearing
ANS
d. Compute the number of 19mm diameter bolts for the connection
ANS
150mm
6mm
Chapter 3 Solutions
Structural Steel Design (6th Edition)
Ch. 3 - Prob. 3.1PFSCh. 3 - Prob. 3.2PFSCh. 3 - Prob. 3.3PFSCh. 3 - Prob. 3.4PFSCh. 3 - Prob. 3.5PFSCh. 3 - Prob. 3.6PFSCh. 3 - Prob. 3.7PFSCh. 3 - Prob. 3.8PFSCh. 3 - Prob. 3.9PFSCh. 3 - Prob. 3.10PFS
Ch. 3 - Prob. 3.11PFSCh. 3 - Prob. 3.12PFSCh. 3 - Prob. 3.13PFSCh. 3 - Prob. 3.14PFSCh. 3 - Prob. 3.15PFSCh. 3 - Prob. 3.16PFSCh. 3 - Prob. 3.17PFSCh. 3 - Prob. 3.18PFSCh. 3 - Prob. 3.19PFSCh. 3 - Prob. 3.20PFSCh. 3 - Prob. 3.21PFSCh. 3 - Prob. 3.22PFSCh. 3 - Prob. 3.23PFSCh. 3 - Prob. 3.24PFSCh. 3 - Prob. 3.25PFSCh. 3 - Prob. 3.26PFSCh. 3 - Prob. 3.27PFSCh. 3 - Prob. 3.28PFSCh. 3 - Prob. 3.29PFSCh. 3 - Prob. 3.30PFSCh. 3 - Prob. 3.31PFSCh. 3 - Prob. 3.32PFSCh. 3 - Prob. 3.33PFSCh. 3 - Prob. 3.34PFSCh. 3 - Determine the LRFD design strength and the ASD...Ch. 3 - Prob. 3.36PFSCh. 3 - Prob. 3.37PFS
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- Subject: Steel design- Bolted Steel Connection *Use NSCP 2015 formula/guide to solve this problem *Use Handwrittenarrow_forwardDetermine the critical net width for the staggered bolted connection as shown in the figure below. The diameter of the bolts is 19 mm. Use depth 4y = 200 mm. %3D x = 0.8y A y y E.arrow_forwardThe 200 mm x 150 mm x 12/5 mm angle has one line of 20 mm diameter bolts in each leg. The bolts are 75 mm on center in each line and are staggered 37.5mm with respect to each other. Fy 248 MPa, Fu-400 MPa. Standard nominal hole diameter of 20 mm bolt is 21mm. Area of the angular section= 4355 mm2. Reduction coefficient U-0.75 CIVIL ENGINEERING STEEL DESIGN Compute The following: a) The effective net area b.)The design strength for LRFD. c) The allowable strength for ASD. 200 75 (1125 67.5 150 1125 1125arrow_forward
- Determine the effective net area of the W16 × 40 shown in the figure. Assume the holes are for 3/4-in Ø bolts. (Ans. 8.53 in2)arrow_forward1arrow_forward1. The tension member shown in Figure 3.4-2 is a PL 58 x 10, and the steel is A36. The bolts are 3/4-inch in diameter. a. Draw the different potential failure lines. b. Compute the effective net area. 22" 2½" 2" 4 3" *₁ 3" ✓ 2" 2. A double-channel shape, 2C10 x 20 steel, Fy = 50 ksi and Fu = 70 ksi, is used for a built-up tension member as shown in the figure. The holes are for 12-inch-diameter bolts. PNA a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. YD Shape A 2" 2" -X Area, Depth, d | 3²²-|-1 3²² | 00 "There is no elevator to success, you have to take the stairs." - Zig Ziglar God bless. Ⓒ O O O Web Thickness, tw in. in. O 4" C10-30 x25 x20 5.87 10.0 10 0.379 % x15.3 4.48 10.0 10 0.240 4 4" Table 1-5 C-Shapes Dimensions Flange Width, b₁ 2 in. in. in.2 in. C15x50 14.7 15.0 15 0.716 1168 3.72 3% 0.650 % x40 11.8 15.0 15 0.520 x33.9 10.0 15.0 15 0.400 % 14 3.52 32 0.650 % %/16 3.40 3% 0.650 % C12-30 8.81 12.0 12 0.510 4 3.17 3% x25 7.34 12.0 12…arrow_forward
- Given: Compute A,, and A, for a 14-in.-wide and ½-in.-thick plate subject to tensile loading with staggered holes as shown in Figure ½" thick- P 2.00" 3.00 4.00 3.00 2.00 A B EF O s=2.50" D G 34" bolts in 13/16" holes Parrow_forwardsniparrow_forwardProblem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4 - 22 mm diameter bolts. 12 mm bolts T12 mm te12 mm P 300 75 75 75 Edge distances = 75 mm %3D dnole for tensile and rupture = dp +3 mm %3D dnole for bearing strength for Lec = d + 1.5 mm Fy = 248 MPa Fu = 400 MPa %3D En 330 MPa %3D Use LRFD design method. Determine the design strength due to tensile rupture strength of plates. (kN)arrow_forward
- An MC12 x 45 is connected through its web with 3 gage lines of 7/8-in Ø bolts. The gage lines are 3 in on center and the bolts are spaced 3 in on center along the gage line. If the center row of bolts is staggered with respect to the outer row, determine the effective net cross-sectional area of the channel. Assume there are four bolts in each line.arrow_forwardDetermine the controlling (lowest) net area of the member. X = 2.69 Y = (6-2.69)/2 Z=0.7 Y" -X Y" 5 @ 1/2" OD O a Do -OHD -(5)-z" bolts -L6 X 4 X 7/16arrow_forwardThe bolted connection shown in Figures is connected with 3/4-in-diameter bolts in standard holes. The plate material is A36 steel. By using strength level design (LRFD), find the available tensile strength of the plates. u=0.8 (5)-¾" bolts 4" C12× 20.7 | 4½" ,3" , 4½" |arrow_forward
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