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Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Question
Chapter 3, Problem 3.37PFS
To determine
The LRFD design strength and the ASD allowable strength of the given section,
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Students have asked these similar questions
A PL40 mm X 250 mm (smaller member) is connected to a gusset
plate (bigger member) as shown. The diameter of the holes are 25
mm. The pitch and gage of the holes are 50 mm and 75 mm,
respectively. The yield strength of the steel is 260 MPa while the
ultimate tensile strength of the steel is 400 MPa. Determine the
design (LRFD) tensile strength of the tension member in kN.
Neglect block shear.
H
G
P
P
D
B
F
C
A
E
A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown.
The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm,
respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the
steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN.
Neglect block shear.
H
FO
E.
• D
A
В
Please answer
Chapter 3 Solutions
Structural Steel Design (6th Edition)
Ch. 3 - Prob. 3.1PFSCh. 3 - Prob. 3.2PFSCh. 3 - Prob. 3.3PFSCh. 3 - Prob. 3.4PFSCh. 3 - Prob. 3.5PFSCh. 3 - Prob. 3.6PFSCh. 3 - Prob. 3.7PFSCh. 3 - Prob. 3.8PFSCh. 3 - Prob. 3.9PFSCh. 3 - Prob. 3.10PFS
Ch. 3 - Prob. 3.11PFSCh. 3 - Prob. 3.12PFSCh. 3 - Prob. 3.13PFSCh. 3 - Prob. 3.14PFSCh. 3 - Prob. 3.15PFSCh. 3 - Prob. 3.16PFSCh. 3 - Prob. 3.17PFSCh. 3 - Prob. 3.18PFSCh. 3 - Prob. 3.19PFSCh. 3 - Prob. 3.20PFSCh. 3 - Prob. 3.21PFSCh. 3 - Prob. 3.22PFSCh. 3 - Prob. 3.23PFSCh. 3 - Prob. 3.24PFSCh. 3 - Prob. 3.25PFSCh. 3 - Prob. 3.26PFSCh. 3 - Prob. 3.27PFSCh. 3 - Prob. 3.28PFSCh. 3 - Prob. 3.29PFSCh. 3 - Prob. 3.30PFSCh. 3 - Prob. 3.31PFSCh. 3 - Prob. 3.32PFSCh. 3 - Prob. 3.33PFSCh. 3 - Prob. 3.34PFSCh. 3 - Determine the LRFD design strength and the ASD...Ch. 3 - Prob. 3.36PFSCh. 3 - Prob. 3.37PFS
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- 3. A plate with width of 300mm and thickness of 20mm is to be connected to two plates of the same width with half the thickness by 24mm diameter bolts, as shown. The rivet holes have a diameter of 2mm larger than the rivet diameter. The plate is A36 steel with yield strength F,-248MPa and ultimate strength F,-400MPa. a. Determine the design strength of the section. b. Determine the allowable strength of the section 24mm 30mmarrow_forwardConsidering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.arrow_forwardA 3/4 in (thickness) X 5 in (height) steel plate is connected to another one through two bolts of nominal diameter 1/2 in in a zig-zag arrangement as shown. Determine the tensile strength capacity Pu of the connection. Review the three limit-states: (a) yielding in the gross area, (b) rup- ture in the overall net tensile area, and (c) block shear strength.arrow_forward
- Take R as 70arrow_forwardTopic:Welded Connection - Civil Engineering -Steel Design *Use latest NSCP/NSCP 2015 formula to solve this problem *Please use hand written to solve this problem A tension member consists of a double angle section with long legs back to back. The angles are attached to a 9.5 mm thick gusset plate. Fu = 400 MPa Fy = 248 MPa for angular section. Fw = 480 MPa for 8 mm fillet weld. Reduction factor U = 0.80 Prop. of One Angle L 125m x 75m x 12.7 m A= 2419 mm2 y=44.45 mm Questions: a) Compute the design strength capacity of one angle. b) Compute the base metal shear strength (gusset plate) per unit length. c) Compute the length L1 and L2.arrow_forwardThe welded girder shown in the accompanying illustration has an external shear VD = 300 k and VL = 350 kat a particular section. Determine the fillet weld size required to fasten the plates to the web if the SMAW process is used. E70. Use LRFD and ASD.arrow_forward
- a welded connection is in eqilibrium under the action of the four forces shown. Knowing that FA=8lbs and FB= 16lbs, determine the magnitudes of other two forces *3dec places all finalarrow_forwardSTEEL ANALYSIS full solution and final answer to 4 decimal places plsarrow_forwardISA 100 x 75 x 10 mm (cross-sectional area = 1650 mm2) Serves as a tensile member. This angle is welded to a gusset plate along A and B appropriately as shown. Assuming the yield strength of the steel to be 260 N/mm². ISA (100 × 75 × 10 mm) B Gusset base With reference to the information given, Determine Area of connected leg Area of outstanding leg i Net effective area of the memberarrow_forward
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