Chapter 3, Problem 3.128P

(a)

Interpretation Introduction

Interpretation:

The balanced equations for the reactions are to be written.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

The coefficients in the balanced equation tell about the number of molecules or moles of each reactant and product involved in the reaction.

(b)

Interpretation Introduction

Interpretation:

The one overall balanced equation that does not include nitrogen monoxide and nitrogen dioxide is to be written.

Concept introduction:

In a balanced chemical equation, the total mass of reactants and products are equal in a balanced chemical equation, thus, it obeyed the law of conservation of mass. Also, the amounts of substances in a balanced chemical reaction are stoichiometrically equivalent to each other.

The coefficients in the balanced equation tell about the number of molecules or moles of each reactant and product involved in the reaction.

(c)

Interpretation Introduction

Interpretation:

The mass of nitric acid form when $1350\text{ t}$ of atmospheric nitrogen is consumed is to be calculated.

Concept introduction:

Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.

Consider the general reaction,

$\text{A}+2\text{B}\to 3\text{C}$

One mole of $\text{A}$ reacts with two moles of $\text{B}$ to produce three moles of $\text{C}$. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.

The conversion factor to convert $\text{t}$ to $\text{kg}$ is as follows:

$\text{1}\text{t}=1000\text{kg}$