Chapter 3, Problem 3.131P

(a)

Interpretation Introduction

Interpretation:

The mass of heme in the sample is to be determined.

Concept introduction:

Mass percent is defined as the mass of a component divided by the total mass of the mixture, multiplied by 100.

The formula to calculate the mass percent is as follows:

  $\text{Mass}\text{percent}=\left(\frac{\text{mass}\text{of}\text{solute}}{\text{mass}\text{of}\text{solution}}\right)100$

(b)

Interpretation Introduction

Interpretation:

The moles of heme in the sample are to be calculated.

Concept introduction:

The expression to calculate the moles of a solute when given mass and molecular mass of compound are given is as follows:

  $\text{Moles}=\frac{\text{mass}}{\text{molar mass}}$        (2)

(c)

Interpretation Introduction

Interpretation:

The mass of iron in the sample is to be determined.

Concept introduction:

Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.

Consider the general reaction,

  $\text{A}+2\text{B}\to 3\text{C}$

One mole of $\text{A}$ reacts with two moles of $\text{B}$ to produce three moles of $\text{C}$. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.

(d)

Interpretation Introduction

Interpretation:

The mass of hemin in the sample is to be determined.

Concept introduction:

Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.

Consider the general reaction,

$\text{A}+2\text{B}\to 3\text{C}$

One mole of $\text{A}$ reacts with two moles of $\text{B}$ to produce three moles of $\text{C}$. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.