Chapter 3, Problem 3.72P

Interpretation Introduction

Interpretation:

The mass of ${\text{H}}_{\text{3}}{\text{BO}}_{\text{3}}$ and ${\text{H}}_{\text{2}}$ formed by the reaction of $43.82{\text{ g B}}_{\text{2}}{\text{H}}_{\text{6}}$ with excess of water is to be calculated.

Concept introduction:

The chemical equation corresponding to the given compound should be balanced properly. Balancing is a hit and trial method where one element is balanced at a time on both sides of the equation. The smallest whole number coefficients are used.

The mole ratio from the balanced chemical equation is used for determining the moles of product.