The mass of H 3 BO 3 and H 2 formed by the reaction of 43.82 g B 2 H 6 with excess of water is to be calculated. Concept introduction: The chemical equation corresponding to the given compound should be balanced properly. Balancing is a hit and trial method where one element is balanced at a time on both sides of the equation. The smallest whole number coefficients are used. The mole ratio from the balanced chemical equation is used for determining the moles of product.

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Chapter 3, Problem 3.72P

Interpretation Introduction

Interpretation:

The mass of H3BO3 and H2 formed by the reaction of 43.82 g B2H6 with excess of water is to be calculated.

Concept introduction:

The chemical equation corresponding to the given compound should be balanced properly. Balancing is a hit and trial method where one element is balanced at a time on both sides of the equation. The smallest whole number coefficients are used.

The mole ratio from the balanced chemical equation is used for determining the moles of product.

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