The bond lengths of the X − H bonds in NH 3 , PH 3 , and SbH 3 are 1.02, 1.42, and 1.71 Å, respectively. Estimate the length of the As − H bond in AsH 3 , the gaseous compound that decomposes on a heated glass surface in Marsh’s test for arsenic. Which of these four hydrides has the weakest X − H bond?
The bond lengths of the X − H bonds in NH 3 , PH 3 , and SbH 3 are 1.02, 1.42, and 1.71 Å, respectively. Estimate the length of the As − H bond in AsH 3 , the gaseous compound that decomposes on a heated glass surface in Marsh’s test for arsenic. Which of these four hydrides has the weakest X − H bond?
Solution Summary: The author explains that the length of the As-H bond in AsH 3 depends on the nuclear charge of an atom and its size. The bond strength is inversely proportional to the bond length.
The bond lengths of the
X
−
H
bonds in
NH
3
,
PH
3
, and
SbH
3
are 1.02, 1.42, and 1.71 Å, respectively. Estimate the length of the
As
−
H
bond in
AsH
3
, the gaseous compound that decomposes on a heated glass surface in Marsh’s test for arsenic. Which of these four hydrides has the weakest
X
−
H
bond?
In the solid state, oxalic acid occurs as
a dihydrate with the formula H2C2O4
C+2H2O. Use this formula to
calculate the formula weight of oxalic
acid. Use the calculated formula
weight and the number of moles
(0.00504mol)
of oxalic acid in each titrated
unknown sample recorded in Table
6.4 to calculate the number of grams
of pure oxalic acid dihydrate
contained in each titrated unknown
sample.
1.
Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their
(2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these
orbitals from the two atoms forming a homonuclear л-bond. Which element would have a
stronger bond, and why?
(4 points)
Chapter 3 Solutions
Student Solutions Manual for Oxtoby/Gillis/Butler's Principles of Modern Chemistry, 8th
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Quantum Molecular Orbital Theory (PChem Lecture: LCAO and gerade ungerade orbitals); Author: Prof Melko;https://www.youtube.com/watch?v=l59CGEstSGU;License: Standard YouTube License, CC-BY