Introduction To Genetic Analysis
12th Edition
ISBN: 9781319114787
Author: Anthony J.F. Griffiths, John Doebley, Catherine Peichel, David A. Wassarman
Publisher: W. H. Freeman
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Chapter 3, Problem 1P
Summary Introduction
To determine: The following -
- a. The probability of X2 17 with 9 pdf.
- b. The probability of X2 17 with 6 pdf.
- c. The rule that is seen in both the calculations.
Introduction. Probability is a mathematical term that is used in mathematics to find out the events that are occurred or about to occur. It is also used in genetics to find out the events which are occurred among the traits or genes,
Expert Solution & Answer
Explanation of Solution
- a. The X2 17 are lies in the p 0.1, as clearly seen in table 3-1 in page number 36 of chapter 3. The probability of the X2 17 with nine pdf is –
- 0.1 X 100 = 10.
Hence the probability is 10%.
- b. The X2 17 are lies in the p 0.1, as clearly seen in table 3-1 in page number 36 of chapter 3. The probability of the X2 17 with six pdf is –
- 0.2 X 100 = 10.
Hence the probability is 10%.
- c. The rules that are found in both the calculations are that the probability value is found based on the table is not accurate but can be found as an approximate value. The p>0.05 of a hypothesis is considered to be accurate, and p<0.05 is considered to be false.
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Students have asked these similar questions
Let X, Y ~ U(0, 1) be independent random variables uniformly distributed over (0, 1) and Z = X+2Y.
(a) Find the LMMSE estimator of X given Z.
(b) Find the MMSE estimator of X given Z. Is LMMSE and MMSE estimator the same?
Calculate the Variance of the following data set:
10, 15, 13, 12, 14
Example
3.5.7
Fish Vertebrae Consider the distribution of vertebrae given in Table 3.5.1. In Exam-
ple 3.5.5 we found that the mean of Y is µy = 21.49. The variance of Y is
VAR(Y) = of = (20 – 21.49) x Pr{Y = 20}
21)
%3D
+ (21 – 21.49)? x Pr{Y
+ (22 – 21.49)? x Pr{Y = 22}
+ (23 – 21.49) x Pr{Y = 23}
= (-1.49) x 0.03 + (-.49) x 0.51
+ (0.51) x 0.40 + (1.51)² × 0.06
= 2.2201 x 0.03 + .2401 x 0.51 + .2601 x 0.40 + 2.2801 x 0.06
= 0.066603 + 0.122451 + 0.10404 + 0.136806
= 0.4299.
The standard deviation of Y is ay = V0.4299 - 0.6557.
%3D
Chapter 3 Solutions
Introduction To Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 43.1PCh. 3 - Prob. 43.2PCh. 3 - Prob. 43.3PCh. 3 - Prob. 43.4PCh. 3 - Prob. 43.5PCh. 3 - Prob. 43.6PCh. 3 - Prob. 43.7PCh. 3 - Prob. 43.8PCh. 3 - Prob. 43.9PCh. 3 - Prob. 43.10PCh. 3 - Prob. 43.11PCh. 3 - Prob. 43.12PCh. 3 - Prob. 43.13PCh. 3 - Prob. 43.14PCh. 3 - Prob. 43.15PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 70PCh. 3 - Prob. 1GSCh. 3 - Prob. 2GSCh. 3 - Prob. 3GS
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