General Chemistry: Principles and Modern Applications (11th Edition)
General Chemistry: Principles and Modern Applications (11th Edition)
11th Edition
ISBN: 9780132931281
Author: Ralph H. Petrucci, F. Geoffrey Herring, Jeffry D. Madura, Carey Bissonnette
Publisher: PEARSON
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Chapter 3, Problem 121SAE
Interpretation Introduction

Interpretation:

The correct option should be determined for the compound C7H7NO2.

17 atoms per mole,

Equal percent’s by mass of C and H,

About twice the percent by mass of O as of N,

About twice the percent by mass of N as of H

Concept introduction:

Number of moles is equal to the ratio of given mass to the molar mass.

The mathematical expression is given by:

Number of moles = Given massMolar mass

Molar mass of the molecule is equal to the sum of the masses of atoms present in the molecule.

The one mole of any substance is equal to the Avogadro number i.e. 6.022×1023 atoms.

Mass percent of an atom = Mass of atomMass of compound×100%

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Chapter 3 Solutions

General Chemistry: Principles and Modern Applications (11th Edition)

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