Genetics: From Genes To Genomes (6th International Edition)
6th Edition
ISBN: 9781260041217
Author: Leland Hartwell Dr., ? Michael L. Goldberg Professor Dr., ? Janice Fischer, ? Leroy Hood Dr.
Publisher: Mcgraw-Hill
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Textbook Question
Chapter 3, Problem 10P
Several genes in humans in addition to the ABO gene (I) give rise to recognizable antigens on the surface of red blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or a negative allele, with positive being dominant to negative. M and N are codominant alleles of the MN gene. The following chart shows several mothers and their children. For each mother-child pair, choose the father of the child from among the males in the right column, assuming one child per male.
| Mother | Child | Males | |
| a. | O M Rh(pos) | B MN Rh(neg) | O M Rh(neg) |
| b. | B MN Rh(neg) | O N Rh(neg) | A M Rh(pos) |
| c. | O M Rh(pos) | A M Rh(neg) | O MN Rh(pos) |
| d. | AB N Rh(neg) | B MN Rh(neg) | B MN Rh(pos) |
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Several genes in humans in addition to the ABO gene () give rise to recognizable antigens on the surface of the red blood cells. The
Rh marker is determined by positive (R) and negative alleles () of gene R, where R is completely dominant to r. The presence of M and
N surface proteins are controlled by two codominant alleles of gene L (LM and LM. For each mother-child pair, choose the father of
the child from among the males in the right column. (Assume that all mothers and fathers are HH; there is no involvement of the
Bombay phenotype.)
Paternal genotypes maybe used once, more than once, or not at all. Each mother-child pair matches with one or more than one
paternal genotype.
Maternal phenotype:
Child phenotype:
Paternal genotype:
Reset
A, M, Rh(neg)
O, M, Rh(pos)
B, N, Rh(neg)
O, N, Rh(pos)
O, M, Rh(neg)
A, MN, Rh(pos)
A, N, Rh(pos)
AB, MN, Rh(pos)
B, N, Rh(pos)
A, MN, Rh(neg)
Genotypes of
possible fathers
AiLMLN rr
BiLMLN RR
ii LNLN rr
ii LMLM rr
AALMLN RR
What would the offspring's blood type be if the mother is type O+ (she is homozygous for Rh factor) and the father is A- (he is homozygous for type A)? Hint: You have to do two Punnett squares. The two Punnett squares must be shown to get the full points. After doing the Punnett squares, write down the possibilities of the offspring’s blood type.
A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has codominant alleles M and N.
If both children are of blood type M in addition to their ABO blood type, list all of the possible parental phenotypes for the ABO, MN and Rh traits.
Chapter 3 Solutions
Genetics: From Genes To Genomes (6th International Edition)
Ch. 3 - For each of the terms in the left column, choose...Ch. 3 - In four-oclocks, the allele for red flowers is...Ch. 3 - The Aa heterozygous snapdragons in Fig. 3.3 are...Ch. 3 - Recall from Chapter 2 Fig. 2.20 that Mendels R...Ch. 3 - In the fruit fly Drosophila melanogaster, very...Ch. 3 - A cross between two plants that both have yellow...Ch. 3 - In radishes, color and shape are each controlled...Ch. 3 - A wild legume with white flowers and long pods is...Ch. 3 - Assuming no involvement of the Bombay phenotype in...Ch. 3 - Several genes in humans in addition to the ABO...
Ch. 3 - Alleles of the gene that determines seed coat...Ch. 3 - One of your fellow students tells you that there...Ch. 3 - In a population of rabbits, you find three...Ch. 3 - In clover plants, the pattern on the leaves is...Ch. 3 - Fruit flies with one allele for curly wings Cy and...Ch. 3 - In certain plant species such as tomatoes and...Ch. 3 - In a species of tropical fish, a colorful orange...Ch. 3 - People heterozygous for normal and nonfunctional...Ch. 3 - Using old Fugate family Bibles and the Perry...Ch. 3 - A rooster with a particular comb morphology called...Ch. 3 - A black mare was crossed to a chestnut stallion...Ch. 3 - Filled-in symbols in the pedigree that follows...Ch. 3 - You perform a cross between two true-breeding...Ch. 3 - a. How would you describe inheritance of flower...Ch. 3 - Suppose the intermediate called Colorless...Ch. 3 - Explain the difference between epistasis and...Ch. 3 - The dominant allele H reduces the number of body...Ch. 3 - Secretors genotypes SS and Ss secrete their A and...Ch. 3 - Normally, wild violets have yellow petals with...Ch. 3 - A woman who is blood type B has a child whose...Ch. 3 - The following table shows the responses of blood...Ch. 3 - Three different pure-breeding strains of corn that...Ch. 3 - In mice, the AY allele of the agouti gene is a...Ch. 3 - A student whose hobby was fishing pulled a very...Ch. 3 - Suppose that blue flower color in a plant species...Ch. 3 - This problem examines possible biochemical...Ch. 3 - Considering your answers to Problem 36, does the...Ch. 3 - You picked up two mice one female and one male...Ch. 3 - Figure 3.21 and Fig. 3.28b both show traits that...Ch. 3 - Three genes in fruit flies affect a particular...Ch. 3 - The garden flower Salpiglossis sinuata painted...Ch. 3 - In foxgloves, three different petal phenotypes...Ch. 3 - In a culture of fruit flies, matings between any...Ch. 3 - Prob. 44PCh. 3 - A couple wants to know the probability that their...Ch. 3 - This problem illustrates why classical geneticists...Ch. 3 - Prob. 47PCh. 3 - Familial hypercholesterolemia FH is an inherited...Ch. 3 - You have come into contact with two unrelated...Ch. 3 - Polycystic kidney disease is a dominant trait that...Ch. 3 - Identical monozygotic twins have similar, but not...Ch. 3 - Using each of the seven coat color genes discussed...
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- The mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your resultarrow_forwardIn humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. The trait is X-linked. A female hemophiliac has a child with a man who is not a hemophiliac. What is the probability that this couple's child is a hemophiliac and what is the child's gender? Your response must include a Punnett square with correct nomenclature.arrow_forwardHemophilia is an X-linked disease associated with the inability to produce specific proteins in the blood-clotting pathway. Shown above is a family pedigree tree in which family members afflicted with the disease are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passing on the disease to their future children (represented by the ? symbol above) because the hemophilia runs in the woman’s family 4.Assuming that the woman in the couple is a carrier, what is the probability that the couple’s first son will have hemophilia?arrow_forward
- 4:33 4 Alger Edit Today 4:31 PM O LIVE Which of the following statements regarding Mendel's observations and Laws are still true and part of our knowledge of genetics today? (Check all that true.) M Two alleles segregate during meiosis, ending up in different gametes. Each pea plant has 2 alleles for every gene, but only contributes one in each gamete. The recombination of alleles in a zygote is completely random. The Law of Independeht Assortment was determined by following three traits in pea plants, TMendle was able to determine his Law of Segregation by following ane trait in pea plants. Every offspring inherits only 1 allele from each parent.arrow_forwardO. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S Farrow_forwardIn humans, the Rh factor genetic information is inherited from our parents, but it is inherited independently of the ABO blood type alleles. In humans, Rh+ individuals have the Rh antigen on their red blood cells, while Rh- individuals do not. There are two different alleles for the Rh factor known as Rh+ and rh. Assume that a dominant gene Rh produces the Rh+ phenotype, and that the recessive rh allele produces the Rh- phenotype. In a population that is in Hardy-Weinberg equilibrium, if 160 out of 200 individuals are Rh+, calculate the frequencies of both alleles.arrow_forward
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