ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
ORGANIC CHEMISTRY SAPLING ACCESS + ETEX
6th Edition
ISBN: 9781319306977
Author: LOUDON
Publisher: INTER MAC
Question
Book Icon
Chapter 28, Problem 28.53AP
Interpretation Introduction

(a)

Interpretation:

Anticipating the isolation of the potentially aromatic hydrocarbon B, a group of chemists irradiated compound A with ultraviolet light. Compound C was obtained as a product instead of B.

ORGANIC CHEMISTRY SAPLING ACCESS + ETEX, Chapter 28, Problem 28.53AP

The reason for compound B might be expected to be unstable in spite of its cyclic array of 4n+2 π electrons is to be stated.

Concept introduction:

The stability of aromatic compounds is high due to their stabilization energy. In order to retain their aromaticity (resultant stabilization energy) aromatic compounds undergo substitution reaction more readily. Aromaticity in compounds is considered only the system having 4n+2 π electrons, planar, cyclic, and should have conjugated π-electrons.

Interpretation Introduction

(b)

Interpretation:

The formation of compound B is allowed by the pericyclic selection rules is to be explained.

Concept introduction:

Pericyclic reactions deal with electrons shift in a concerted manner. Moreover, in these reactions the breaking of reactant bonds and the formation of product bonds are formed at the same time.i.e., without the formation of intermediates. The word ‘pericyclic’ means around the cycle. Notably, the pericyclic reactions are classified as electrocyclic, cycloaddition and sigmatropic reactions based on the activation of reaction, the number of electrons involved and the stereochemistry outcome of the reactions. The selection rules of pericyclic reaction deal mostly on the rates of reaction and does not tell anything about position of equilibrium and equilibrium constant values.

Interpretation Introduction

(c)

Interpretation:

The formation of the observed product C is to be explained.

Concept introduction:

Pericyclic reactions deal with electrons shift in a concerted manner. Moreover, in these reactions the breaking of reactant bonds and the formation of product bonds are formed at the same time.i.e., without the formation of intermediates. The selection rules of pericyclic reaction deal mostly on the rates of reaction and does not tell anything about position of equilibrium and equilibrium constant values.

Blurred answer
Students have asked these similar questions
Draw the two products of the reaction. H₂C. CH₂ H :0: CH3 CH₂ +1
Show work. Don't give Ai generated solution
None
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY