(a)
Interpretation:
Retention factors for each compound should be calculated.
Concept introduction:
Following equation can be used in calculation of retention factors.
(b)
Interpretation:
Distribution constants for each compound should be calculated.
Concept introduction:
The distribution constant can be calculated as follows:
(c)
Interpretation:
Selectivity factor for methylcyclohexane and methylcyclohexene should be calculated.
Concept introduction:
For the calculation of selectivity factor for methylcyclohexane and methylcyclohexene, the following formula will be used:
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Chapter 26 Solutions
Principles of Instrumental Analysis
- answer a and barrow_forwardA juice concentrate was colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the sample solution and various concentrations of the standard glucose solution were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbances at 480 nm for distilled water, glucose standard, and for the sample are 0.052, 1.702, and 0.926, respectively. What is the reducing sugar concentration (mg/mL) in the juice concentrate? The equation of the line was plotted to be: y = 1.6656x - 0.0885 0.578 mg/mL 577.9 mg/mL 57.7 mg/mL 5.78 mg/mLarrow_forwardRetention times with a 1.10 m gas-liquid chromatographic column: air, 18.0 s; methyl acetate, 1.98 min.; methyl propionate, 2.24 min; methyl n-butyrate, 7.93 min.Base widths of the last three peaks: 0.19; 0.23 and 0.79 min, respectively. Calculate:a) the value of k for each compound,b) the alpha value for each pair of adjacent peaks,c) the theoretical number of plates and the plate height of each column;d) the resolution of every two adjacent compounds.arrow_forward
- This is a Biochemistry lab question. For the lab we are spectrophotometrically determining the pka of PNP based on different pHs. I have a sigmoid graph of the absborances of PNP at different pHs at 400 nm. I have pH on the x-axis and absorbance on the y-axis. How do a calculate the pka based off of this graph?arrow_forwardAliquots of a 0.5 mg/mL standard of BSA were used to construct a standard curve for the Bradford protein assay. The tubes contained the following amounts of the BSA solution: 0, 20, 40, 60, 80, 100 μL. Each sample then had water added to make the final volume 100 μL. The corresponding absorbencies after adding Bradford reagent were the following: 0, 0.05, 0.09, 0.14, 0.19, and 0.22. If you took 20 μL of an unknown and added 80 μL of water, mixed, took 10 μL of the mixture and 90 μL of water and added the Bradford reagent and saw an absorbance of 0.08, what was the protein concentration of the undiluted unknown to one decimal place?arrow_forwardPeak Retention Time (minutes) Area 1.201 136501204 acetone 2.011 1253056 toluene ortho-product para-product 3.201 8340750 3.350 14890645 a) What was the relative percent yield of the ortho-product? b) What was the relative percent yield of the para-product? c) What was the relative percent yield of the product?arrow_forward
- Propofol (Diprivan) is a very common short-term anesthetic and sedative, and its structure is shown to the right. OH The mass spectrum of propofol is given below. Label the molecular ion peak on the spectrum and suggest a structure for the ion responsible for the 163 m/z base peak. pts) Rel. Intensity 100 80 60 40 20 0.0 0.0 40 litla gula dala 80 m/z 120 160 200 propofolarrow_forwardIf you are interested in separating a mixture of volatile compounds, which technique do you think would work best? ○ ICPMS ○ HPLC О АА ○ UV/Vis O LOD GC ○ TLCarrow_forwardBelow is the questionarrow_forward
- present HPLC chromatogram of dicinnamalacetone.arrow_forwardInterpretation of the peaks?IUPAC Name / Trivial Name of the compound?arrow_forwardMTN-SA 36ll O *I § 100% 13:39 KAMVA KD 9. During an assay of paracetamol by UV an analyst prepares a series of calibration solutions containing approximately 3-15 mcg/mL paracetamol as follows: • 141.7 mg of pure paracetamol was added to a 200 mL volumetric flask. • 0.1 M NaOH (50 mL) was added, the mixture well shaken and made up to volume with deionized water • 10 mL of the above solution was diluted to 100 mL a) What is the concentration of the final diluted solution in mcg/mL? Answer = mcg/mL (1 decimal) b) What volume of the diluted solution is required to prepare 100 mL of a 11 mcg/mL standard ution? Answer = mL (1 decimal) 33arrow_forward
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning