Principles of Instrumental Analysis
Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
Question
100%
Book Icon
Chapter 26, Problem 26.20QAP
Interpretation Introduction

(a)

Interpretation:

In order to obtain desired resolution of 1.5, the number of plates should be calculated.

Concept introduction:

The resolution can be calculated as follows:

R=(tR)B(tR)A(tR)B×N44R×(tR)B(tR)B(tR)A=NN=[4R×(tR)B(tR)B(tR)A]2where:N=Numberofplates(tR)A,(tR)B=RetentiontimesofspeciesAandBrespectivelyR=Resolution

Interpretation Introduction

(b)

Interpretation:

Height of the column should be calculated.

Concept introduction:

The plate height can be calculated as follows:

H=LNwhere:H=PlateheightL=LengthofcolumnpackingN=Numberofplates

Interpretation Introduction

(c)

Interpretation:

Retention time of the methylcyclohexene should be calculated.

Concept introduction:

Retention time is directly proportional to the resolution. Therefore, following equation can be used.

(tR)1(tR)2=(R)12(R)22

Blurred answer
Students have asked these similar questions
Two components in an HPLC separation have retention times thatdiffer by 22 s. The first peak elutes in 10.5 min and the peakwidths are approximately equal. Use a spreadsheet to find theminimum number of theoretical plates needed to achieve thefollowing resolution, Rs, values: 0.50, 0.75, 0.90, 1.0, 1.10, 1.25,1.50, 1.75, 2.0, and 2.5. How would the results change if peak 2were twice as broad as peak 1?
Analysis of an unknown plant extract yield two peaks X and Y in a chromatogram, 15.65 and 17.03 min respectively in a 30.0 cm column. The peak base width for X is 1.06 and 1.15 for Y. The analysis gave a column resolution equal to?
13. Electrospray time-of-flight mass spectrometry was used to analyze the eluate from a high-performance liquid chromatography separation. The mass spectrum of one chromatographic peak, containing a protein of unknown molecular mass, displays MH peaks at m/z = 5 654.208, 5 277.326, 4 947.590, 4 656.613, 4 397.990, and 4 166.576. Find the average molecular mass (M) of the neutral protein and its standard deviation.
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:9781285640686
Author:Skoog
Publisher:Cengage
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT