To determine the two molecules involved in the connecting link from the citric acid cycle to the urea cycle. Concept introduction: A urea cycle is a cyclic biochemical pathway that involves the production of urea using ammonium ions and aspartate molecules as nitrogen sources. The desired product of the urea cycle is urea. It constitutes 4 steps. In step 1 carbamoyl phosphate transfers its carbamoyl group to ornithine to produce citrulline. Citrulline then condenses with aspartate in the second step to form argininosuccinate which then cleaves in the third step to form arginine and fumarate. In the final step, arginine reacts with water to produce urea. The citric acid cycle is a series of eight chemical reactions used to release energy by all aerobic organisms. The acetyl part of acetyl CoA is oxidized with the release of ATP and carbon dioxide.

Question

Want to see the full answer?

Answer 1

Question

Chapter 26, Problem 26.110EP

Interpretation Introduction

Interpretation: To determine the two molecules involved in the connecting link from the citric acid cycle to the urea cycle.

Concept introduction: A urea cycle is a cyclic biochemical pathway that involves the production of urea using ammonium ions and aspartate molecules as nitrogen sources. The desired product of the urea cycle is urea. It constitutes 4 steps. In step 1 carbamoyl phosphate transfers its carbamoyl group to ornithine to produce citrulline. Citrulline then condenses with aspartate in the second step to form argininosuccinate which then cleaves in the third step to form arginine and fumarate. In the final step, arginine reacts with water to produce urea.

The citric acid cycle is a series of eight chemical reactions used to release energy by all aerobic organisms. The acetyl part of acetyl CoA is oxidized with the release of ATP and carbon dioxide.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please finish the chart at the bottom. Some of the answers have been filled in.

9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…

Normal dive (for diving humans) normal breathing dive normal breathing Oz level CO2 level urgent need to breathe Oz blackout zone high CO2 triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. How might the location and slope of the O₂ line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO₂ line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?