Organic Chemistry Study Guide and Solutions
Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 24, Problem 24.39AP
Interpretation Introduction

(a)

Interpretation:

Whether αDglucopyranose and βDglucopyranose are epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated.

Concept introduction:

Sugars show different types of isomerism. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.

Expert Solution
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Answer to Problem 24.39AP

The compounds, αDglucopyranose and βDglucopyranose are anomers as well as diastereomers of each other.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  1

Explanation of Solution

The compounds, αDglucopyranose and βDglucopyranose are anomers because their stereochemistry is different at anomeric carbon. Anomeric carbon is carbon 1 in aldose or carbon 2 in ketose.

They are diastereomers also as they are not mirror images of each other. The structure of both the compounds is shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  2

Figure 1

Conclusion

These two compounds are anomers as well as diastereomers as shown in Figure 1.

Interpretation Introduction

(b)

Interpretation:

Whether αDglucopyranose and αDmannopyranose are epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated.

Concept introduction:

Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.

Expert Solution
Check Mark

Answer to Problem 24.39AP

The compounds, αDglucopyranose and αDmannopyranose are epimers as well as diastereomers of each other.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  3

Explanation of Solution

Both the above structures of αDglucopyranose and αDmannopyranose are diastereomers as they are not mirror images. They are epimers as they differ in stereochemistry at carbon 2, H and OH bonds are present on different sides of carbon atom as shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  4

Figure 2

Conclusion

The compounds αDglucopyranose and αDmannopyranose are epimers and diastereomers as shown in Figure 2.

Interpretation Introduction

(c)

Interpretation:

Whether βDmannopyranose and βLmannopyranose are epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated.

Concept introduction:

Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.

Expert Solution
Check Mark

Answer to Problem 24.39AP

The compounds, βDmannopyranose and βLmannopyranose are enantiomers as shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  5

Explanation of Solution

Sugars can be divided into two groups based on the symmetry of carbon atoms. If the molecule has asymmetric carbon atom it will have a non superimposable mirror image. The non superimposable mirror images are known as enantiomers. As the given compounds are non super imposable mirror images of each other they are enantiomers. This can be well explained by the illustrations shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  6

Figure 3

Conclusion

These two compounds βDmannopyranose and βLmannopyranose are enantiomers of each other as shown in Figure 3.

Interpretation Introduction

(d)

Interpretation:

Whether αDribofuranose and αDribopyranose are epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated.

Concept introduction:

Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.

Expert Solution
Check Mark

Answer to Problem 24.39AP

The compounds, αDribofuranose and αDribopyranose are constitutional isomers as they have same molecular formula but different chemical structure as shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  7

Explanation of Solution

As the isomers are the compounds, having similar chemical formula but different structures. These two compounds have same chemical formula. The chemical structure is of these two compounds is quite different as shown in Figure 4.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  8

Figure 4

In the above shown compounds, one is a pentose sugar furanose while the other is a hexose sugar pyranose.

Conclusion

These two compounds, αDribofuranose and αDribopyranose are constitutional isomers as shown in Figure 4.

Interpretation Introduction

(e)

Interpretation:

Whether DGlucose and αDglucopyranose are epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated.

Concept introduction:

Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons.

Expert Solution
Check Mark

Answer to Problem 24.39AP

Aldehyde form of DGlucose and αDglucopyranose are constitutional isomers. Their chemical structure is different but molecular formula is same as shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  9

Explanation of Solution

As the isomers are the compounds, having similar chemical formula but different structures. Both the above structures are constitutional isomers as shown below in the Figure.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  10

Figure 5

In the above shown compounds, one is a ring structure having keto group while the other is open ring structure having aldehyde as the functional group. The chemical formula of the given compounds is same but their properties are totally different.

Conclusion

The given compounds DGlucose and αDglucopyranose are different in chemical structure and therefore their properties are different. So, they are constitutional isomers as shown in Figure 5.

Interpretation Introduction

(f)

Interpretation:

Whether the compounds, methylαDfructofuranoside and 2OmethylαDfructofuranose are enantiomers. epimers, anomers, enantiomers, diastereomers, constitutional isomers or none of the above is to be stated

Concept introduction:

Sugars show different types of isomerism between molecules. They may be enantiomers, epimers, anomers, or diastereomers depending upon chirality and plane of symmetry in molecules. It also depends on stereochemistry of different carbons. The naming of the same compound can be done in different manners.

Expert Solution
Check Mark

Answer to Problem 24.39AP

The compounds, methylαDfructofuranoside and 2OmethylαDfructofuranose are identical compounds only the way of naming is different.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  11

Explanation of Solution

The structure of methylαDfructofuranoside or 2OmethylαDfructofuranose is shown below.

Organic Chemistry Study Guide and Solutions, Chapter 24, Problem 24.39AP , additional homework tip  12

Figure 6

So, the compound is same, they are identical. In first name it is taken as methyl derivative of αDfructofuranoside as in second name methyl is taken on carbon attached to oxygen atom which is again the α carbon on atom. They are identical compounds not isomers.

Conclusion

The compound shown in Figure 6 can be named as methylαDfructofuranoside as well as 2OmethylαDfructofuranose. Both are the name of the same structure.

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