Concept explainers
(a)
Interpretation:
The products expected when D-ribose is reacted with dilute is to be stated.
Concept introduction:
The
Answer to Problem 24.35AP
The product obtained when D-ribose is reacted with dilute is shown below.
Explanation of Solution
The product obtained when D-ribose is reacted with dilute is shown below.
Figure 1
The oxidation of D-ribose into D-ribaric acid occurs in the presence of dilute nitric acid.
The product obtained when D-ribose is reacted with dilute is shown in Figure 1.
(b)
Interpretation:
The products expected when D-ribose is reacted with is to be stated.
Concept introduction:
Kiliani-Fischer process is is the reaction pathway by which an aldose is extended by one carbon unit. The first step of this reaction is the attack of the cyanide group on the carbonyl carbon of the aldehyde group resulting in the formation of the cyanohydrins. The cyanohydrins thus formed is reduced to imine with catalytic hydrogenation. The imine thus formed can easily be hydrolyzed by into aldose and ammonium ion.
Answer to Problem 24.35AP
The products obtained when D-ribose is reacted with are shown below.
Explanation of Solution
The products obtained when D-ribose is reacted with are shown below.
Figure 2
The D-ribose is converted into cyanohydrins by the nucleophilic attack of the cyanide group on the carbonyl carbon of the aldehyde group.
The products obtained when D-ribose is reacted with are shown in Figure 2.
(c)
Interpretation:
The products expected when the product of part (b) is reacted with and is to be stated.
Concept introduction:
Kiliani-Fischer process is is the reaction pathway by which an aldose is extended by one carbon unit. The first step of this reaction is the attack of the cyanide group on the carbonyl carbon of the aldehyde group resulting in the formation of the cyanohydrins. The cyanohydrins thus formed is reduced to imine with catalytic hydrogenation. The imine thus formed can easily be hydrolyzed by into aldose and ammonium ion.
Answer to Problem 24.35AP
The products obtained when the product of part (b) is reacted with and are shown below.
Explanation of Solution
The products obtained when the product of part (b) is reacted with and are shown below.
Figure 3
The product of part (b) is the cyanohydrin of D-ribose which is then converted into the extended aldose, altrose and allose. The catalytic hydrogenation of cyanohydrin into imine is done by . The imine then formed is hydrolyzed into the altrose and allose by .
The products obtained when the product of part (b) is reacted with and are shown in Figure 3.
(d)
Interpretation:
The products expected when D-ribose is reacted with is to be stated.
Concept introduction:
A monosaccharide is converted into cyclic acetals on reaction with alcohols in the presence of acidic conditions. The hydroxide group right to the oxygen atom in the pyranose ring structure is methylated and result in the formation of acetal.
Answer to Problem 24.35AP
The product obtained when D-ribose is reacted with is shown below.
Explanation of Solution
The product obtained when D-ribose is reacted with is shown below.
Figure 4
The D-ribose on reaction with methanol and hydrochloric acid is converted into the acetal. The acetal formed is found in both forms alpha and beta regardless of the configuration of D-ribose.
The product obtained when D-ribose is reacted with is shown in Figure 4.
(e)
Interpretation:
The product obtained when the product of part (d) is reacted with (excess) and is to be stated.
Concept introduction:
The methylation of the hydroxyl group of sugars is an important reaction. The methylation of hydroxyl groups is done with the help of methylating agent dimethyl sulfate in the presence of strong base sodium hydroxide.
Answer to Problem 24.35AP
The product obtained when the product of part (d) is reacted with (excess) and is shown below.
Explanation of Solution
The product obtained when the product of part (d) is reacted with (excess) and is shown below.
Figure 5
The four products of part (d) are alkylated in the strong base sodium hydroxide. The sodium hydroxide takes up the acidic proton of alcohol groups and converts them to alkoxide ion form. This alkoxide ion then attacks on the dimethyl sulfate (also a methylating agent) and take up the methyl group simultaneously eliminating the methyl sulfate group.
The product obtained when the product of part (d) is reacted with (excess) and is shown in Figure 5.
Want to see more full solutions like this?
Chapter 24 Solutions
Organic Chemistry
- The following observations are obtained after a D-hexose was made to react with several reagents: (1) The reactions of a D-hexose with (a) to (d) below yields an aldaric acid (a) NH₂OH, (b) (CH3CO)₂O, NaOCOCH 3, and, (c) NaOCH3, and then, (d) HNO3, H₂O (2) HNO3 oxidation of the same D-hexose gives an aldaric acid. Predict the structures of the three (3) possible hexoses that can undergo the above reactions?arrow_forwardPredict the structure of the product formed(s) when the following triglyceride is treated with each reagent: (a) NaOH in water (b) H₂/Ni (c) O3, then (CH3)2S (d) KMnO4 in water, warm O CH₂OC(CH2)CH=CH(CH2)7CH3 CHOC(CH2)7CH-CH(CH2)7CH3 CH₂OC(CH2)7CH=CH(CH₂)7CH3 CHOICarrow_forwardRibose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four- membered, five-membered, or six-membered ring. To determine which ring is formed, ribose is treated with methanol in the presence of an acid catalyst. The products are then isolated and treated with NaIO4 then with H3O+. OH HO OH OH Ribose, C5H10O5 H MeOH H* A & B isomeric cyclic acetals with formula C6H₁2O5 1. NalO4 2. H₂O* MeOH products Assuming that ribose formed a six-membered ring cyclic hemiacetal, draw the structure of the sodium periodate digestion products. • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.arrow_forward
- 3a. 3b. 3c 3d. 3e. CO₂ clavulanic acid CH₂-OH H Answer the following questions about clavulanic acid. Does clavulanic acid inhibit D-alanyl-D-alanine transpeptidase? Does clavulanic acid contain a ß-lactam? Does clavulanic acid contain a thiazolium ring? What is the result of the treatment of penicillinase with clavulanic acid? Does clavulanic acid form a covalent acyl-enzyme intermediate with penicillinase?arrow_forwardRibose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. To determine which ring is formed, ribose is treated with methanol in the presence of an acid catalyst. The products are then isolated and treated with NaIO, then with H₂O*. HO OH OH OH Ribose, C5H10O5 H 9.81 ** MeOH H* A & B isomeric cyclic acetals with formula C6H12O5 Assuming that ribose formed a five-membered ring cyclic hemiacetal, draw the structure of the sodium periodate digestion products. ▼ • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. 1. NalO4, 2. H₂O* MeOH products 4 SIF Previous Nextarrow_forwardEmil Fischer synthesized l-gulose, an unusual aldohexose that reduces to give d-glucitol.Suggest a structure for this l sugar, and show how l-gulose gives the same alditol asd-glucose. (Hint: d-Glucitol has ¬CH2OH groups at both ends. Either of these primaryalcohol groups might have come from reduction of an aldehyde.)arrow_forward
- Kindly answer question f,g,harrow_forward(a) (i) Write an equation showing the formation of a triacylglycerol (Molecule A) thatcontains equimolar amounts of myristoleic, capric and linolenic acids. Myristoleic acid: CH3(CH2)5CH=CH(CH2)7CO2HCapric acid: CH3(CH2)8CO2HLinolenic acid: CH3CH2(CH=CHCH2)3(CH2)6CO2H (ii) Draw the structure of the partially hydrogenated product of Molecule A.arrow_forwardIdentify the organic functional group and reaction type for the following reaction. The reactant is a(n) - carboxylic acid hexose - Aldohexose - aldotetrose -deoxyhexose -carboxylic acid tetrose - ketohexose The product is a(n) - carboxylic acid tetrose - aldotetrose -alcohol hexose -aldohexose -carboxylic acid hexose - alcohol tetrose The reaction type is - hemiacetal formation -hydrolysis -oxidation( Benedict’s) -acetal formation -reduction( hydrogenation) - mutarotationarrow_forward
- Draw the structure of a carbohydrate with four b-D-glucopyranosyl units connected by b(1®4) glycosidic linkages, with the second unit being connected via an a(1®6) glycosidic linkage by a side chain having two a-D-galactopyranosyl units connected by an a(1®4) glycosidic linkage.arrow_forwardThe carbonyl group in d-galactose may be isomerized from C1 to C2 by brief treatmentwith dilute base (by the enediol rearrangement, Section 23-7). The product is the C4epimer of fructose. Draw the furanose structure of the product.arrow_forwardTreatment of a 258 mg sample of amylopectin by the methylation and hydrolysis procedure described yielded 12.4 mg of 2,3‑di‑O‑methylglucose. Determine what percentage of the glucose residues in amylopectin contained an (α1→6) branch. (Assume that the average molecular weight of a glucose residue in amylopectin is 162 g/mol and the molecular weight of 2,3‑di‑O‑methylglucose is 208 g/mol.) ( α1→6) branched glucose residues: %arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning