In Fig. 24-41 a , a particle of elementary charge + e is initially at coordinate z = 20 am on the dipole axis (here a z axis) through an electric dipole, on the positive side of the dipole. (The origin of z is at the center of the dipole.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = −20 nm, on the negative side of the dipole axis. Figure 24-41 b gives the work W a done by the force moving the panicle versus the angle θ that locates the particle relative to the positive direction of the z axis. The scale of the vertical axis is set by W as = 4.0 × 10 −30 J. What is the magnitude of the dipole moment? Figure 24-41 Problem 22.
In Fig. 24-41 a , a particle of elementary charge + e is initially at coordinate z = 20 am on the dipole axis (here a z axis) through an electric dipole, on the positive side of the dipole. (The origin of z is at the center of the dipole.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = −20 nm, on the negative side of the dipole axis. Figure 24-41 b gives the work W a done by the force moving the panicle versus the angle θ that locates the particle relative to the positive direction of the z axis. The scale of the vertical axis is set by W as = 4.0 × 10 −30 J. What is the magnitude of the dipole moment? Figure 24-41 Problem 22.
In Fig.
24-41
a, a particle of elementary charge +e is initially at coordinate z = 20 am on the dipole axis (here a z axis) through an electric dipole, on the positive side of the dipole. (The origin of z is at the center of the dipole.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = −20 nm, on the negative side of the dipole axis. Figure 24-41b gives the work Wa done by the force moving the panicle versus the angle θ that locates the particle relative to the positive direction of the z axis. The scale of the vertical axis is set by Was = 4.0 × 10−30 J. What is the magnitude of the dipole moment?
In Figure (a), a particle of charge te is initially at coordinate z = 45 nm on the dipole axis through an electric dipole, on the positive side
of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is
at coordinate z = -45 nm. Figure (b) gives the work W, done by the force moving the particle versus the angle that locates the particle.
The scale of the vertical axis is set by Was = 4.0 x 10-30 J. What is the magnitude of the dipole moment?
Number
€
te
8
Units
W. (10-30 л
(b)
-W
In Figure (a), a particle of charge +e is initially at coordinate z = 20 nm on the dipole axis through an electric dipole, on the positive side of the dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle θ that locates the particle. The scale of the vertical axis is set by Was = 4.0 × 10-30 J. What is the magnitude of the dipole moment?
How much work is required to turn an electric dipole 180 in a uniform electric field of magnitude E = 46.0 N/C if the dipole moment has a magnitude of p = 3.02 *10-25 C m and the initial angle is 64?
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