![Organic Chemistry](https://www.bartleby.com/isbn_cover_images/9781305080485/9781305080485_largeCoverImage.gif)
a) CH3CO2Et + CH3CH2CO2Et
Interpretation:
The structures of the possible products, indicating predominant product if any, when ethylacetate and ethyl propionate undergo Claisen condensation reaction are to be given.
Concept introduction:
The Claisen condensation reaction involves a reversible condensation between two molecules of an ester that has α-hydrogen atoms in the presence of one equivalent of a base like sodium ethoxide. The product obtained is a β-keto ester. In the reaction an alcohol molecule is eliminated and the product has an acyl group of one of the reactant molecule attached to the α-carbon of the second molecule.
To give:
The structures of the possible products, indicating predominant product if any, when ethylacetate and ethyl propionate undergo Claisen condensation reaction.
b) C6H5CO2Et + C6H5CH2CO2Et
Interpretation:
The structures of the possible products, indicating predominant product if any, when ethylbenzoyate and ethylphenylacetate undergo Claisen condensation reaction are to be given.
Concept introduction:
The Claisen condensation reaction involves a reversible condensation between two molecules of an ester that has α-hydrogen atoms in the presence of one equivalent of a base like sodium ethoxide. The product obtained is a β-keto ester. In the reaction an alcohol molecule is eliminated and the product has an acyl group of one of the reactant molecule attached to the α-carbon of the second molecule.
To give:
The structure of the possible product, indicating predominant product if any, when ethylbenzoyate and ethylphenylacetate undergo Claisen condensation reaction.
c) EtOCO2Et + cyclohexanone
Interpretation:
The structures of the possible products, indicating predominant product if any, when ethoxyethylformate and cyclohexanone undergo Claisen condensation reaction are to be given.
Concept introduction:
The Claisen condensation reaction involves a reversible condensation between two molecules of an ester that has α-hydrogen atoms in the presence of one equivalent of a base like sodium ethoxide. The product obtained is a β-keto ester. In the reaction an alcohol molecule is eliminated and the product has an acyl group of one of the reactant molecule attached to the α-carbon of the second molecule.
To give:
The structures of the possible products, indicating predominant product if any, when ethoxyethylformate and cyclohexanone undergo Claisen condensation reaction.
d) C6H5CHO + CH3CH2Et
Interpretation:
The structures of the possible products, indicating predominant product if any, when benzaldehyde and ethylformate undergo Claisen condensation reaction are to be given.
Concept introduction:
The Claisen condensation reaction involves a reversible condensation between two molecules of an ester that has α-hydrogen atoms in the presence of one equivalent of a base like sodium ethoxide. The product obtained is a β-keto ester. In the reaction an alcohol molecule is eliminated and the product has an acyl group of one of the reactant molecule attached to the α-carbon of the second molecule.
To give:
The structures of the possible products, indicating predominant product if any, when benzaldehyde and ethylacetate undergo Claisen condensation reaction.
![Check Mark](/static/check-mark.png)
Trending nowThis is a popular solution!
![Blurred answer](/static/blurred-answer.jpg)
Chapter 23 Solutions
Organic Chemistry
- Q1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forward
- %Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forward
- Nonearrow_forwardCarbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forwardHow many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of H2SO4 and in the final volume (2.000 L) and assume random error.arrow_forward
- Macroscale and Microscale Organic ExperimentsChemistryISBN:9781305577190Author:Kenneth L. Williamson, Katherine M. MastersPublisher:Brooks Cole
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305080485/9781305080485_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577190/9781305577190_smallCoverImage.gif)