FUND.OF GEN CHEM CHAP 1-13 W/ACCESS
16th Edition
ISBN: 9781323406038
Author: McMurry
Publisher: PEARSON C
expand_more
expand_more
format_list_bulleted
Question
Chapter 23.7, Problem 23.19P
Interpretation Introduction
Interpretation:
The reason for the passive diffusion of glucose back out of the cell has to be explained.
Concept Introduction:
Passive diffusion:
The transport of ions in the cell membrane which doesn’t need any energy, because the substances move from high concentration to low concentration, in this process only ions which are non-polar and small in size are allowed.
Glycolysis process:
The process in which the breakdown of glucose into pyruvic acid, this whole process generates two ATP’s.
The process serves as the foundation for both aerobic and anaerobic
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Proteolysis increases during the early phases of fasting, but later it decreases as the body adapts to using alternative energy sources. Given that feedback control mechanisms have not been described for intracellular proteases, how might you explain these apparent changes in protease activity?
Why does the lack of glucose 6- phosphatase activity in the brain and muscle make good physiological sense?
Glycolysis can occur under both aerobic and anaerobic conditions. Why is glycolysis called an anaerobic pathway?
Chapter 23 Solutions
FUND.OF GEN CHEM CHAP 1-13 W/ACCESS
Ch. 23.1 - Use Figure 23.1 to identify the family of lipids...Ch. 23.2 - Prob. 23.2PCh. 23.2 - Prob. 23.3PCh. 23.2 - Prob. 23.4KCPCh. 23.3 - Prob. 23.1CIAPCh. 23.3 - Prob. 23.2CIAPCh. 23.3 - Prob. 23.3CIAPCh. 23.3 - Prob. 23.5PCh. 23.3 - Prob. 23.6PCh. 23.3 - Prob. 23.7KCP
Ch. 23.4 - Prob. 23.8PCh. 23.4 - Prob. 23.9PCh. 23.4 - Prob. 23.10PCh. 23.4 - Prob. 23.11PCh. 23.5 - Prob. 23.12PCh. 23.5 - Draw the structure of the sphingomyelin that...Ch. 23.5 - Draw the structure of the glycerophospholipid that...Ch. 23.5 - Prob. 23.16PCh. 23.7 - Prob. 23.17KCPCh. 23.7 - Prob. 23.4CIAPCh. 23.7 - Prob. 23.6CIAPCh. 23.7 - Prob. 23.7CIAPCh. 23.7 - Prob. 23.8CIAPCh. 23.7 - Prob. 23.18PCh. 23.7 - Prob. 23.19PCh. 23.7 - Prob. 23.20KCPCh. 23 - The fatty acid composition of three...Ch. 23 - Prob. 23.23UKCCh. 23 - According to the fluid-mosaic model (Figure 23.7),...Ch. 23 - Dipalmitoylphosphatidylcholine (DPPC) is a...Ch. 23 - Prob. 23.26APCh. 23 - Prob. 23.27APCh. 23 - Prob. 23.28APCh. 23 - Prob. 23.29APCh. 23 - Differentiate between saturated, monounsaturated,...Ch. 23 - Are the carboncarbon double bonds in naturally...Ch. 23 - Prob. 23.32APCh. 23 - Prob. 23.33APCh. 23 - Which of these fatty acids has the lower melting...Ch. 23 - Which of these fatty acids has the higher melting...Ch. 23 - Prob. 23.36APCh. 23 - Prob. 23.37APCh. 23 - Prob. 23.38APCh. 23 - Prob. 23.39APCh. 23 - What function does a wax serve in a plant or...Ch. 23 - Prob. 23.41APCh. 23 - Prob. 23.42APCh. 23 - What kind of lipid is spermacetia fat, a wax, or a...Ch. 23 - Prob. 23.44APCh. 23 - Prob. 23.45APCh. 23 - Prob. 23.46APCh. 23 - Prob. 23.47APCh. 23 - Prob. 23.48APCh. 23 - Prob. 23.50APCh. 23 - Prob. 23.52APCh. 23 - Prob. 23.53APCh. 23 - Describe the difference between a triacylglycerol...Ch. 23 - Why are glycerophospholipids, rather than...Ch. 23 - Prob. 23.56APCh. 23 - Prob. 23.57APCh. 23 - Why are glycerophospholipids more soluble in water...Ch. 23 - Prob. 23.59APCh. 23 - Prob. 23.60APCh. 23 - Prob. 23.61APCh. 23 - Draw the structure of a glycerophospholipid that...Ch. 23 - Prob. 23.63APCh. 23 - What is a major function of cholesterol in your...Ch. 23 - Prob. 23.65APCh. 23 - Prob. 23.66APCh. 23 - Prob. 23.67APCh. 23 - Explain how a micelle differs from a membrane...Ch. 23 - Prob. 23.69APCh. 23 - Prob. 23.70APCh. 23 - Prob. 23.71APCh. 23 - Prob. 23.72APCh. 23 - Prob. 23.73APCh. 23 - Prob. 23.74APCh. 23 - Prob. 23.75APCh. 23 - Draw the structure of a triacylglycerol made from...Ch. 23 - Prob. 23.79CPCh. 23 - Prob. 23.80CPCh. 23 - Explain why cholesterol is not saponifiable.Ch. 23 - Draw cholesterol acetate. Is this molecule...Ch. 23 - Prob. 23.83CPCh. 23 - Prob. 23.84CPCh. 23 - Prob. 23.85CPCh. 23 - Prob. 23.86CPCh. 23 - Prob. 23.88GP
Knowledge Booster
Similar questions
- Glucose is phosphorylated to glucose-6-phosphate by hexokinase in the first step of the glycolytic pathway to trap it in the cell, as G6P cannot diffuse across the lipid bilayer. This reaction also decreases the concentration of free glucose, favoring additional import of the molecule. However, this has a postive standard free energy of 3 kcal per mole. To favor this reaction, hydrolysis of ATP is coupled, which has a standard free energy of -7 kcal per mole. Determine the actual free energy change in kcal/mole for the following conditions: Glucose concentration: 4.5 mM ATP conc: 3.79 mM G6P conc. 0.052 mM ADP conc: 0.12 mM inorganic phosphate conc: 1.3 mM temperature: 313 K Ans. in 3 SFs.arrow_forwardThe enzyme Phosphofructokinase (PFK) is a key regulator of glycolysis. A) Does ATP bind the PFK allosteric siteor the active site? B) Does high amount of ATP in the cell activate or inhibit PFK? Why? C)What do you suppose happens to glucose if glycolysis is inhibited in the cell?arrow_forward2-Deoxyglucose or 2-DG is a glucose analog that binds to hexokinase (the first rate- limiting enzyme of glycolysis) in cells. 2-DG cannot undergo further glycolysis. Which of the following would you predict in cells treated with 2-DG? Select all that apply. Cellular depletion of ATP under anaerobic conditions Decreased viability of tumor cells Increased viability of tumor cells Increased activation of AMPK, a key regulator of cellular metabolismarrow_forward
- You have the following pathway: If an isolated liver cell runs out of glucose, the cell will break down glycogen into Glucose-1-Phosphate (Glucose-1-P). The isolated liver cell will then use the enzyme phosphoglucomutase to convert Glucose-1-P to Glucose-6-P, which can enter glycolysis. If you remove all glucose and add a drug that inhibits phosphoglucomutase, which molecule will most likely accumulate in this system? A. Glucose B. Glucose 1 phosphate C. Glucose 6 phosphate D. Lactate E. CO2arrow_forwardGlucose-6-phosphatase is located inside the endoplasmic reticulum. Describe the probable symptoms of a defect in G6P transport across the endoplasmic reticulum membrane.arrow_forwardThe Warburg effect is where tumor cells preferentially catabolize glucose to lactate even in the presence of oxygen (aerobic glycolysis), whereas normal cells preferentially catabolize glucose to carbon dioxide (oxidative phosphorylation). Treatment of tumor cells with the lactate dehydrogenase inhibitor NCI-737 blocks ATP production. Which of the following statements about NCI-737 treated tumor cells are MOST correct? 1) AGglycolysis is negative 2) AGglycolysis is positive 3) AG" for glycolysis is negative 4) AG" for glycolysis is positive 5) NAD+/NADH decreases 6) NAD+/NADH increases 1, 4, 6 1, 3, 5 2, 4, 6 2, 3, 6 2, 3, 5arrow_forward
- Consider an alternative glycolysis pathway that starts with the phosphorylation of glucose to give glucose-6-phosphate. This (hypothetical) pathway exists in a (hypothetical) organism that does not express glucose-6-phosphate isomerase. Instead, the next step of this hypothetical pathway is a Glucose-6-Phosphate Aldolase. Draw the product or products that would be obtain by the reaction of Glucose – 6 – Phosphate with Glucose – 6 Phosphate Aldolase. Assume the reaction is completely irreversible. Explain in 1-3 sentences how you obtained your answerarrow_forwardIn the pathways of cell metabolism, 1) glycolysis does NOT occur in the mitochondria, AND 2) the proton gradient in oxidative phosphorylation occurs through a PASSIVE transport process. True Falsearrow_forwardOne of the earliest responses to cellular injury is a rapid increase in the levels of enzymes in the pentose phosphate pathway. About ten days after an injury, levels of glucose 6-phosphate dehydrogenase and 6-phosphogluconate dehydrogenase in heart tissue are 20 to 30 times higher than normal. However the levels of glycolytic enzymes are only 10% to 20% of normal. Explain this phenomenon.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- BiochemistryBiochemistryISBN:9781319114671Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.Publisher:W. H. FreemanLehninger Principles of BiochemistryBiochemistryISBN:9781464126116Author:David L. Nelson, Michael M. CoxPublisher:W. H. FreemanFundamentals of Biochemistry: Life at the Molecul...BiochemistryISBN:9781118918401Author:Donald Voet, Judith G. Voet, Charlotte W. PrattPublisher:WILEY
- BiochemistryBiochemistryISBN:9781305961135Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougalPublisher:Cengage LearningBiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage LearningFundamentals of General, Organic, and Biological ...BiochemistryISBN:9780134015187Author:John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. PetersonPublisher:PEARSON
Biochemistry
Biochemistry
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:W. H. Freeman
Lehninger Principles of Biochemistry
Biochemistry
ISBN:9781464126116
Author:David L. Nelson, Michael M. Cox
Publisher:W. H. Freeman
Fundamentals of Biochemistry: Life at the Molecul...
Biochemistry
ISBN:9781118918401
Author:Donald Voet, Judith G. Voet, Charlotte W. Pratt
Publisher:WILEY
Biochemistry
Biochemistry
ISBN:9781305961135
Author:Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:Cengage Learning
Biochemistry
Biochemistry
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Cengage Learning
Fundamentals of General, Organic, and Biological ...
Biochemistry
ISBN:9780134015187
Author:John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher:PEARSON