General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 23.3, Problem 23.5P
Interpretation Introduction
Interpretation:
Energy change in the hydrolysis of creatine phosphate to creatine and the phosphorylation of ADP to ATP needs to be calculated. Whether it is energy released or required in this reaction needs to be explained.
Concept Introduction:
Creatine phosphate is a phosphorylated creatine molecule synthesized in the body from the amino acid guanine. Creatine phosphate is an energy storage molecule in muscles that can release high energy and produce ATP.
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Chapter 23 Solutions
General, Organic, & Biological Chemistry
Ch. 23.2 - Prob. 23.1PCh. 23.3 - Prob. 23.2PCh. 23.3 - Prob. 23.3PCh. 23.3 - Prob. 23.4PCh. 23.3 - Prob. 23.5PCh. 23.4 - Prob. 23.6PCh. 23.4 - Prob. 23.7PCh. 23.4 - Prob. 23.8PCh. 23.4 - Prob. 23.9PCh. 23.4 - Prob. 23.10P
Ch. 23.5 - Prob. 23.11PCh. 23.5 - Prob. 23.12PCh. 23.5 - Prob. 23.13PCh. 23.6 - Prob. 23.14PCh. 23.6 - Prob. 23.15PCh. 23.6 - Prob. 23.16PCh. 23 - Prob. 23.17PCh. 23 - Prob. 23.18PCh. 23 - Prob. 23.19PCh. 23 - Prob. 23.20PCh. 23 - Prob. 23.21PCh. 23 - Prob. 23.22PCh. 23 - Prob. 23.23PCh. 23 - Prob. 23.24PCh. 23 - Prob. 23.25PCh. 23 - Prob. 23.26PCh. 23 - Prob. 23.27PCh. 23 - Prob. 23.28PCh. 23 - The phosphorylation of glucose with forms glucose...Ch. 23 - Prob. 23.30PCh. 23 - Prob. 23.31PCh. 23 - Prob. 23.32PCh. 23 - Prob. 23.33PCh. 23 - Prob. 23.34PCh. 23 - Prob. 23.35PCh. 23 - Prob. 23.36PCh. 23 - Prob. 23.37PCh. 23 - Classify each substance as an oxidizing agent, a...Ch. 23 - Prob. 23.39PCh. 23 - Prob. 23.40PCh. 23 - Prob. 23.41PCh. 23 - Prob. 23.42PCh. 23 - Prob. 23.43PCh. 23 - Prob. 23.44PCh. 23 - Prob. 23.45PCh. 23 - Prob. 23.46PCh. 23 - Prob. 23.47PCh. 23 - Prob. 23.48PCh. 23 - Prob. 23.49PCh. 23 - Prob. 23.50PCh. 23 - Prob. 23.51PCh. 23 - Prob. 23.52PCh. 23 - Prob. 23.53PCh. 23 - Prob. 23.54PCh. 23 - Prob. 23.55PCh. 23 - Prob. 23.56PCh. 23 - Prob. 23.57PCh. 23 - Prob. 23.58PCh. 23 - Prob. 23.59PCh. 23 - Prob. 23.60PCh. 23 - Prob. 23.61PCh. 23 - Prob. 23.62PCh. 23 - Prob. 23.63PCh. 23 - Prob. 23.64PCh. 23 - Prob. 23.65PCh. 23 - Prob. 23.66PCh. 23 - Prob. 23.67PCh. 23 - Prob. 23.68PCh. 23 - Prob. 23.69PCh. 23 - Prob. 23.70PCh. 23 - Prob. 23.71PCh. 23 - Prob. 23.72PCh. 23 - Prob. 23.73PCh. 23 - Prob. 23.74PCh. 23 - Prob. 23.75CPCh. 23 - Prob. 23.76CP
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- The first step of the metabolic process known as glycolysis is the conversion of glucose to glucose- 6-phosphate. This process has a positive value for rG' Glucose + Pi Glucose-6-phosphate + H2O rG' = +13.8 kJ/mol-rxn This reaction is coupled to the hydrolysis of ATP ATP + H2O ADP + Pi rG' = -30.5 kJ/mol-rxn What is the sum of these two equations and the value of rG' for the coupled reaction? Is the coupled reaction product-favored at equilibrium?arrow_forwardThe average adult consumes approximately 11,700 kJ per day. Assuming that the metabolic pathways leading to ATP synthesis operate at 50% thermodynamic efficiency, about 5850 kJ ends up in the form of synthesized ATP. The average adult consumes approximately 11,700 kJ per day. Assuming that the metabolic pathways leading to ATP synthesis operate at 50% thermodynamic efficiency, about 5850 kJ ends up in the form of synthesized ATP. Imagine that creatine phosphate, rather than ATP, is the universal energy carrier molecule in the human body. Assume that the cellular concentrations of creatine phosphate, creatine, and phosphate are 21.7 mM, 2.17×10-3 mM, and 6.30 mM, respectively. Calculate the weight of creatine phosphate that would need to be consumed each day by a typical adult human if creatine phosphate could not be recycled. Estimate the free energy of hyrdolysis of creatine phosphate under cellular conditions to determine how many moles are required. Use the standard…arrow_forwardrank in order that releases most to least amount of energyarrow_forward
- Describeenergy consumed vs released in reactions. Differentiate between endergonic vs exergonic reactions, anabolism vs catabolism, and coupled reactions.arrow_forwardDetermine the direction that each of the reactions will progress. Assume that the reactants and products are present in equimolar amounts. The standard free energy of hydrolysis of ATP is –30.5 kJ/mol. fructose+ATP ____fructose 6‑phosphate+ADP The standard free energy of hydrolysis for fructose 6‑phosphate is −15.9 kJ/mol. 3‑phosphoglycerate+ATP___1,3‑bisphosphoglycerate+ADP The standard free energy of hydrolysis for 1,3‑bisphosphoglycerate is −49.3 kJ/mol. creatine+ATP___creatine phosphate+ADP The standard free energy of hydrolysis for creatine phosphate is –43.0 kJ/mol.arrow_forwardGive an example of a coupled reaction showing an overall change in free energy.arrow_forward
- The oxidation of 1 mol of glucose supplies enough meta-bolic energy to form 36 mol of ATP. Oxidation of 1 mol of a typ-ical dietary fat like tristearin (C₅₇H₁₁₆O₆) yields enough energyto form 458 mol of ATP. (a) How many molecules of ATP canform per gram of glucose? (b) Per gram of tristearin?arrow_forward1- Find the amount of energy released (in kcal) by: • 1 gram of proteins • 1 gram of carbohydrates • 1 gram of fatsarrow_forwardThe AG" of the dephosphorylation of phosphocreatine is -43.0 kJ/mol. Phosphocreatine → creatine +Pi; -43.0kJ/mol When coupled to the phosphorylation of ADP to ATP (+30.5kJ/mol) ADP +Pi → ATP; +30.5 kJ/mol calculate the actual, physiological AG for the following reaction in kJ/mol: Phosphocreatine + ADP creatine + ATP at 37°C, with concentrations as follows: Phosphocreatine = 0.715 mM creatine = 0.566 mM ADP = 0.431 mM ATP = 2.382 mMarrow_forward
- Which metabolic pathway is directly responsible for the production of the most ATP molecules?arrow_forwardBased on the following information for phosphoglucoisomerase, calculate the equilbrium constant and round to the nearest tenths place. R = 8.3145 J/mol⋅K ΔG∘’ = -14.2 kJ/molarrow_forwardNeed help with 5arrow_forward
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