The mean orbital radius r (in units of 10 5 km ) of a moon of Saturn can be modeled by the equation r = 1.93 t 2 / 3 , where t is the time in (Earth) days for the moon to complete one orbit about the planet. Use this model to estimate the instantaneous rate of change of r with respect to t when t = 0.602 day (the orbital period of Saturn’s moon Atlas).
The mean orbital radius r (in units of 10 5 km ) of a moon of Saturn can be modeled by the equation r = 1.93 t 2 / 3 , where t is the time in (Earth) days for the moon to complete one orbit about the planet. Use this model to estimate the instantaneous rate of change of r with respect to t when t = 0.602 day (the orbital period of Saturn’s moon Atlas).
The mean orbital radius
r
(in units of
10
5
km
) of a moon of Saturn can be modeled by the equation
r
=
1.93
t
2
/
3
, where
t
is the time in (Earth) days for the moon to complete one orbit about the planet. Use this model to estimate the instantaneous rate of change of
r
with respect to
t
when
t
=
0.602
day (the orbital period of Saturn’s moon Atlas).
Question 2
Let F be a solenoidal vector field, suppose V × F = (-8xy + 12z², −9x² + 4y² + 9z², 6y²), and let
(P,Q,R) = V²F(.725, —.283, 1.73). Then the value of sin(2P) + sin(3Q) + sin(4R) is
-2.024
1.391
0.186
-0.994
-2.053
-0.647
-0.588
-1.851
1 pts
1 pts
Let F and G be vector fields such that ▼ × F(0, 0, 0) = (0.76, -9.78, 3.29), G(0, 0, 0) = (−3.99, 6.15, 2.94), and
G is irrotational. Then sin(5V (F × G)) at (0, 0, 0) is
Question 1
-0.246
0.072
-0.934
0.478
-0.914
-0.855
0.710
0.262
.
answer
Chapter 2 Solutions
Calculus Early Transcendentals, Binder Ready Version
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