
Concept explainers
(a)
Interpretation: The structure and the systematic name of the product for the given reaction have to be given.
Concept introduction:
An
Systematic Name: It is a standardized name given for a chemical compound in systematic manner. Any organic molecule can be named by using IUPAC (International Union for Pure and applied chemistry) rules. IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule. It can be any alkyl group and carboxy, amino, cyano etc…
Suffix represents the substituent present in the molecule. It can be any alkene,
Root word represents the longest continuous carbon skeleton present in the organic molecule.
When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo.
IUPAC naming for Alkane:
Name the main chain: Find the longest carbon chain and name the chain according to the number of carbon atoms it contains; is also the suffix part of the name.
Number the carbon atoms in the main chain: The carbons are numbered, in which the substituents must get lowest possible numbers.
Identify the substituents, and number each: The number at where substituents are present has to be noted. The substituents written as prefix.
Write the names as a single word: Use the hyphen to separate the numbers from the different prefix; commas to separate numbers. If two or more different substituents are present, arrange them in alphabetical order. If two or more identical substituents are present, use prefixes di-, tri-, tetra-, but this particular prefix should not be used for alphabetizing purpose.
(b)
Interpretation: The structure and the systematic name of the product for the given reaction have to be given.
Concept introduction: An alkyne undergo halogenation reaction when it is treated with halogens. The addition of four halogen atoms takes place on the carbon-carbon triple bond. The product formed is called as tetrahaloalkanes.
Systematic Name: It is a standardized name given for a chemical compound in systematic manner. Any organic molecule can be named by using IUPAC (International Union for Pure and applied chemistry) rules. IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule. It can be any alkyl group and carboxy, amino, cyano etc…
Suffix represents the substituent present in the molecule. It can be any alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton present in the organic molecule.
When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo.
IUPAC naming for Alkane:
Name the main chain: Find the longest carbon chain and name the chain according to the number of carbon atoms it contains; is also the suffix part of the name.
Number the carbon atoms in the main chain: The carbons are numbered, in which the substituents must get lowest possible numbers.
Identify the substituents, and number each: The number at where substituents are present has to be noted. The substituents written as prefix.
Write the names as a single word: Use the hyphen to separate the numbers from the different prefix; commas to separate numbers. If two or more different substituents are present, arrange them in alphabetical order. If two or more identical substituents are present, use prefixes di-, tri-, tetra-, but this particular prefix should not be used for alphabetizing purpose.

Want to see the full answer?
Check out a sample textbook solution
Chapter 23 Solutions
Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
- Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forwardEpoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forward
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning

