(a) Interpretation: The stepwise mechanism to explain the given result is to be drawn. Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

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Answer 1

Question

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

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Answer 2

Question

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

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Answer 3

Question

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

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Answer 4

Question

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

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Answer 5

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Answer 6

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Answer 7

Chapter 23, Problem 23.78P

Interpretation Introduction

(a)

Interpretation: The stepwise mechanism to explain the given result is to be drawn.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Answer 8

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Answer 9

Interpretation Introduction

(b)

Interpretation: The validation of the fact that optically pure isomer is obtained regardless of the amount of base used in litorene is to be stated with an explanation.

Concept introduction: Carbonyl compounds in presence of base, loses its alpha hydrogen to form enolate. Enolates have negatively charged oxygen with adjacent carbon-carbon double bond. Enolates are resonance stabilized species.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 23 - Problem 23.1 Draw the enol or keto tautomer(s) of...Ch. 23 - Draw a stepwise mechanism for the following...Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Which CH bonds in the following molecules are...Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - When ethyl acetoacetate (CH3COCH2CO2CH2CH3) is...Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains the stepwise mechanism to explain the given result. Carbonyl compounds in presence of base, lose their alpha hydrogen to form enolate.

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Chapter 23 Solutions