Chapter 22, Problem 95IAE

Interpretation Introduction

(a)

Interpretation:

To show the % P = 0.436 × (% ${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ ) and % BPL = 2.185 × (% ${\text{P}}_{\text{4}}{\text{O}}_{\text{10}}$ ).

Concept introduction:

It is very well known that the phosphate rock is on of the significant commercial source of phosphorus element. The term BPL has been defined as the content of phosphate which is expressed as ${\text{Ca}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$ of all the phosphate materials.

Interpretation Introduction

(b)

Interpretation:

To determine the significance of % BPL greater than 100.

Concept introduction:

It is very well known that the phosphate rock is on of the significant commercial source of phosphorus element. The term BPL has been defined as the content of phosphate which is expressed as ${\text{Ca}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$ of all the phosphate materials.

Interpretation Introduction

(c)

Interpretation:

To determine the % BPL of a typical phosphate rock.

Concept introduction:

It is very well known that the phosphate rock is on of the significant commercial source of phosphorus element. The term BPL has been defined as the content of phosphate which is expressed as ${\text{Ca}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$ of all the phosphate materials.