(a) Interpretation: The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined. Concept introduction: The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules. ΔHcombustion = ∑ ΔHf(product) - ∑ ΔHf(reactant)

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Answer 1

Question

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

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Students have asked these similar questions

In the Thermo Fisher application note about wine analysis (Lesson 3), the following chromatogram was collected of nine components of wine. If peak 3 has a retention time of 3.15 minutes and a peak width of 0.070 minutes, and peak 4 has a retention time of 3.24 minutes and a peak width of 0.075 minutes, what is the resolution factor between the two peaks? [Hint: it will help to review Lesson 2 for this question.] MAU 300 200 T 34 5 100- 1 2 CO 6 7 8 9 0 2.4 2.6 2.8 3.0 3.2 3.4 3.6 3.8 4.0 4.2 4.4 4.6 4.8 5.0 5.2 Minutes 3.22 0.62 1.04 O 1.24

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8. Choose the compound that will produce the spectrum below and assign the signals to the corresponding protons. 2 4 3 ō (ppm) OH 4 6 6 СОН 2 1 0

Answer 2

Question

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

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Answer 3

Question

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

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Answer 4

Question

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

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Answer 5

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Answer 6

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Answer 7

Chapter 22, Problem 72E

Interpretation Introduction

(a)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per mole should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Answer 8

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Answer 9

Interpretation Introduction

(b)

Interpretation:

The alkane (methane, ethane, propane or butane) which evolves the greatest amount of heat during combustion on the basis of per gram also the alkane desirable for reducing the emission of carbon dioxide should be determined.

Concept introduction:

The standard enthalpy of combustion can be defined as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water. The standard enthalpy of combustion can be calculated with the help of enthalpy of formation of reactant and product molecules.

ΔHcombustion = ∑ΔHf(product) - ∑ΔHf(reactant)

Answer 10

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Answer 11

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Answer 12

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Answer 13

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Solution Summary: The author defines the standard enthalpy of combustion as the heat change for the combustion of one mole of substance that leads to the formation of carbon dioxide and water.

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