
Concept explainers
(a)
Interpretation: The electronic configuration, magnetic character and the number of unpaired electrons for the given set of high spin complexes has be determined.
Concept introduction: The
The properties of the coordination compounds depend upon the primary and secondary valancy of the metal ion in the coordination sphere. The electrical conductivity depends upon the number of ions that are produced by complex.
The strong-field ligands results in pairing of electrons present in the complex and leads to diamagnetic species , while the low-field ligand do not have tendency to pair up the electrons therefore forms paramagnetic species.
The strong field ligands lead to splitting to a higher extent than the weak field ligands and the
The five d orbitals get divided into two sets that is
Electronic configuration: It is defined as the distribution of electrons present in the atom over orbitals following certain rules like electrons starts filling the lower energy orbital to higher energy, pairing of electrons does not occur until all the orbitals are singly filled and finally no electrons present in orbital can have same set of quantum numbers.
Oxidation State: It is the number which defines number of electrons that are gained or lost by a given chemical substance.
(a)

Answer to Problem 44PS
The given complex contains 4 unpaired electrons since the given complex is high spin complex where electrons present in higher energy d orbitals. Therefore, the given complex is paramagnetic.
Explanation of Solution
Examining the given complex shows that
The oxidation state for
Now considering the charge of metal atom the outer electrons present in the given complex is six distributed over d orbitals as follows,
The above configuration clearly shows that there exist 4 unpaired electrons since the given condition says that it is high spin complex where pairing of electrons does not occur and the electrons tends to present at higher level of d orbitals hence the given complex is paramagnetic.
(b)
Interpretation: The electronic configuration, magnetic character and the number of unpaired electrons for the given set of high spin complexes should be determined.
Concept introduction: The transition metal atoms have tendency to form complex compounds that are linked to the certain neutral or ionic species which leads to the formation of coordination compounds. There exists a large number of coordination compounds that have a large number of applications in the chemical industry as well as in daily life.
The properties of the coordination compounds depend upon the primary and secondary valancy of the metal ion in the coordination sphere. The electrical conductivity depends upon the number of ions that are produced by complex.
The strong-field ligands results in pairing of electrons present in the complex and leads to diamagnetic species , while the low-field ligand do not have tendency to pair up the electrons therefore forms paramagnetic species.
The strong field ligands lead to splitting to a higher extent than the weak field ligands and the wavelength of light absorbed depends on the energy gap that is produced by a particular ligand.
The five d orbitals get divided into two sets that is
Electronic configuration: It is defined as the distribution of electrons present in the atom over orbitals following certain rules like electrons starts filling the lower energy orbital to higher energy, pairing of electrons does not occur until all the orbitals are singly filled and finally no electrons present in orbital can have same set of quantum numbers.
Oxidation State: It is the number which defines number of electrons that are gained or lost by a given chemical substance.
(b)

Answer to Problem 44PS
The given complex contains 5 unpaired electron and it is paramagnetic.
Explanation of Solution
Examining the given complex shows that
The oxidation state for
Now considering the charge of metal atom the outer electrons present in the given complex is five distributed over d orbitals as follows,
The above configuration clearly shows that there exist 5 unpaired electrons since the given condition says that it is high spin complex where pairing of electrons does not occur and the electrons tends to present at higher level of d orbitals hence the given complex is paramagnetic.
(c)
Interpretation: The electronic configuration, magnetic character and the number of unpaired electrons for the given set of high spin complexes should be determined.
Concept introduction: The transition metal atoms have tendency to form complex compounds that are linked to the certain neutral or ionic species which leads to the formation of coordination compounds. There exists a large number of coordination compounds that have a large number of applications in the chemical industry as well as in daily life.
The properties of the coordination compounds depend upon the primary and secondary valancy of the metal ion in the coordination sphere. The electrical conductivity depends upon the number of ions that are produced by complex.
The strong-field ligands results in pairing of electrons present in the complex and leads to diamagnetic species , while the low-field ligand do not have tendency to pair up the electrons therefore forms paramagnetic species.
The strong field ligands lead to splitting to a higher extent than the weak field ligands and the wavelength of light absorbed depends on the energy gap that is produced by a particular ligand.
The five d orbitals get divided into two sets that is
Electronic configuration: It is defined as the distribution of electrons present in the atom over orbitals following certain rules like electrons starts filling the lower energy orbital to higher energy, pairing of electrons does not occur until all the orbitals are singly filled and finally no electrons present in orbital can have same set of quantum numbers.
Oxidation State: It is the number which defines number of electrons that are gained or lost by a given chemical substance.
(c)

Answer to Problem 44PS
The given complex contains 4 unpaired electrons and it is paramagnetic.
Explanation of Solution
Examining the given complex shows that
The oxidation state for
Now considering the charge of metal atom the outer electrons present in the given complex is four distributed over d orbitals as follows,
The above configuration clearly shows that there exist 4 unpaired electrons since the given condition says that it is high spin complex where pairing of electrons does not occur and the electrons tends to present at higher level of d orbitals hence the given complex is paramagnetic.
(d)
Interpretation: The electronic configuration, magnetic character and the number of unpaired electrons for the given set of high spin complexes should be determined.
Concept introduction: The transition metal atoms have tendency to form complex compounds that are linked to the certain neutral or ionic species which leads to the formation of coordination compounds. There exists a large number of coordination compounds that have a large number of applications in the chemical industry as well as in daily life.
The properties of the coordination compounds depend upon the primary and secondary valancy of the metal ion in the coordination sphere. The electrical conductivity depends upon the number of ions that are produced by complex.
The strong-field ligands results in pairing of electrons present in the complex and leads to diamagnetic species , while the low-field ligand do not have tendency to pair up the electrons therefore forms paramagnetic species.
The strong field ligands lead to splitting to a higher extent than the weak field ligands and the wavelength of light absorbed depends on the energy gap that is produced by a particular ligand.
The five d orbitals get divided into two sets that is
Electronic configuration: It is defined as the distribution of electrons present in the atom over orbitals following certain rules like electrons starts filling the lower energy orbital to higher energy, pairing of electrons does not occur until all the orbitals are singly filled and finally no electrons present in orbital can have same set of quantum numbers.
Oxidation State: It is the number which defines number of electrons that are gained or lost by a given chemical substance.
(d)

Answer to Problem 44PS
The given complex contains 5 unpaired electron and it is paramagnetic.
Explanation of Solution
Examining the given complex shows that
The oxidation state for
Now considering the charge of metal atom the outer electrons present in the given complex is four distributed over d orbitals as follows,
The above configuration clearly shows that there exist 5 unpaired electrons since the given condition says that it is high spin complex where pairing of electrons does not occur and the electrons tends to present at higher level of d orbitals hence the given complex is paramagnetic.
Want to see more full solutions like this?
Chapter 22 Solutions
Chemistry & Chemical Reactivity
- Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH. How many mL of NaOH are needed to reach the first equivalence point? How many mL of NaOH are needed to reach the second equivalence point?arrow_forwardIncluding activity, calculate the solubility of Pb(IO3)2 in a matrix of 0.020 M Mg(NO3)2.arrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M KBr.arrow_forward
- Including activity, calculate the pH of a 0.010 M HCl solution with an ionic strength of 0.10 M.arrow_forwardCan I please get the graph 1: Concentration vs. Density?arrow_forwardOrder the following series of compounds from highest to lowest reactivity to electrophilic aromatic substitution, explaining your answer: 2-nitrophenol, p-Toluidine, N-(4-methylphenyl)acetamide, 4-methylbenzonitrile, 4-(trifluoromethyl)benzonitrile.arrow_forward
- Ordene la siguiente serie de compuestos de mayor a menor reactividad a la sustitución aromática electrofílica, explicando su respuesta: ácido bencenosulfónico, fluorobenceno, etilbenceno, clorobenceno, terc-butilbenceno, acetofenona.arrow_forwardCan I please get all final concentrations please!arrow_forwardState the detailed mechanism of the reaction of benzene with isopropanol in sulfuric acid.arrow_forward
- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning





