Concept explainers
(a)
Interpretation:
The compounds required for the condensation to synthesise the given compound are to be stated.
Concept introduction:
In base-catalysed aldol condensation, nucleophilic addition of an enolate ion takes place on a carbonyl group. In first step, an alpha proton is removed to produce enolate ion. It adds to the carbonyl group. In the next step, protonation of alkoxide gives the aldol product.
(b)
Interpretation:
The compounds required for the condensation to synthesise the given compound are to be stated.
Concept introduction:
Michael addition is a conjugate addition or 1,4-addition of a resonance stablised carbanion to a conjugated double bond. The conjugate double bond of
(c)
Interpretation:
The compounds required for the condensation to synthesis the given compound are to be stated.
Concept introduction:
Michael addition is a conjugate addition or 1,4-addition of a resonance stablised carbanion to conjugated double bond. The conjugate double bond of
Want to see the full answer?
Check out a sample textbook solutionChapter 22 Solutions
Organic Chemistry (9th Edition)
- A DEPT NMR spectrum is shown for a molecule with the molecular formula of C5H12O. Draw the structure that best fits this data. 200 180 160 140 120 100 一盆 00 40 8- 20 ppm 0 Qarrow_forwardDon't used hand raitingarrow_forwardShown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H. H. +N=C H H H Cl: Click and drag to start drawing a structure. : ? g B S olo Ar B Karrow_forward
- Don't used hand raitingarrow_forwardS Shown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H H = HIN: H C. :0 H /\ H H Click and drag to start drawing a structure. ×arrow_forwardPlease help me figure out these calculation and what should be plotted. These are notes for my chemistry class.arrow_forward
- Nonearrow_forwardNonearrow_forwardPart II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning